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Some fixed point theorems for mappings satisfying contractive conditions of integral type
Fixed Point Theory and Applications volume 2014, Article number: 69 (2014)
Abstract
Five fixed point theorems for mappings satisfying contractive conditions of integral type in complete metric spaces are proved. Two examples are added to illustrate the results obtained.
MSC:54H25.
1 Introduction and preliminaries
Rhoades [1] and Branciari [2] proved the following fixed point theorems for the weakly contraction mapping and contractive mapping of integral type, respectively, which are generalizations of the Banach fixed point theorem.
Theorem 1.1 ([1])
Let T be a mapping from a complete metric space into itself satisfying
where is continuous and nondecreasing such that ψ is positive on , and . Then T has a unique fixed point in X.
Theorem 1.2 ([2])
Let T be a mapping from a complete metric space into itself satisfying
where is a constant and . Then T has a unique fixed point such that for each .
Recently several years, the researchers in [3–14] and others continued the study of Rhoades and Branciari, proved some fixed point and common fixed point theorems for various generalized weakly contraction mappings and contractive mappings of integral type in complete metric spaces, Banach spaces, modular spaces and symmetric spaces. Suzuki [15] proved that contractive condition of integral type in complete metric spaces is a special case of Meir-Keeler type.
The objective of this article is both to introduce several mappings satisfying contractive conditions of integral type, one of which extends the mapping (1.1) and is different from the mapping (1.2), and to provide sufficient conditions which ensure the existence of fixed points and convergence of iterative methods for these mappings in complete metric spaces. Two nontrivial examples are given to explain the main results obtained.
Throughout this paper, we assume that , , ℕ denotes the set of all positive integers and
For a self mapping T in a metric space and , define
Lemma 1.1 ([10])
Let and be a nonnegative sequence with . Then
Lemma 1.2 ([10])
Let and be a nonnegative sequence. Then
if and only if .
2 Main results
Now we prove the existence, uniqueness, and iterative approximations of fixed points for the mappings (2.1), (2.8), and (2.19)∼(2.21), respectively.
Theorem 2.1 Let be in and T be a mapping from a complete metric space into itself satisfying
Then T has a unique fixed point such that for each .
Proof Let x be an arbitrary point in X. Suppose that there exists some with . Clearly,
that is, is a fixed point of T. Suppose that for each . It follows from (2.1) and that
which yields
which implies that there exists a constant c with . Suppose that . Put . It is easy to see that there exists a subsequence of satisfying . Since ψ is lower semicontinuous and , it follows that . Using (2.1), Lemma 1.1 and , we get
which is impossible. Hence and
Now we prove that is a Cauchy sequence. If it is not a Cauchy sequence, then there exist a constant and two subsequences and of such that is minimal in the sense that and . It follows that . Observe that
and
Letting in (2.3) and (2.4) and using (2.2), we infer that
Put
Clearly, there exists a subsequence of such that
Since ψ is lower semicontinuous, it follows from (2.5), (2.6), and that . By means of (2.1), (2.5), (2.6), Lemma 1.1, and , we deduce that
which is a contradiction. Thus is a Cauchy sequence. Since is complete, it follows that there exists such that
Next we prove that a is a fixed point of T. In view of (2.1), (2.7), and Lemma 1.2, we obtain
which implies that
which together with Lemma 1.2 gives
Consequently, we have
that is, .
Lastly, we prove that a is a unique fixed point of T in X. Suppose that T has another fixed point . It follows from (2.1), , and that
which is a contradiction. This completes the proof. □
Remark 2.1 In the case for all , Theorem 2.1 reduces to Theorem 1.1. On the other hand, the example below demonstrates that Theorem 2.1 is different from Theorem 1.2.
Example 2.1 Let be endowed with the Euclidean metric , and be defined by
and
Obviously, . Let . It is clear that
which imply that
which gives
that is, (2.1) holds. Thus the conditions of Theorem 2.1 are satisfied. It follows from Theorem 2.1 that T has a unique fixed point and for each .
In order to verify that Theorem 1.2 is useless in proving the existence of fixed points of T, we need to show that (1.2) does not hold. Otherwise, (1.2) holds, that is, there exists some constant satisfying
which yields
which means that
which is a contradiction.
Theorem 2.2 Let be in and T be a mapping from a complete metric space into itself satisfying
Then T has a unique fixed point such that for each .
Proof Let x be an arbitrary point in X. If for some , then there is nothing to prove. Now suppose that for all . Note that
because
Now we prove that
Or else there exists some such that . Making use of (2.8) and (2.9), we know that
which is a contradiction. Note that (2.10) means that there exists a constant c with
Suppose that . Set . Obviously, there exists a subsequence of such that . Since ψ is lower semicontinuous, it follows from that . On account of (2.8)∼(2.11), Lemma 1.1, and , we arrive at
which is absurd. Hence and (2.2) holds. Suppose that is not a Cauchy sequence. It follows that there exist a constant and two subsequences and of such that is minimal in the sense that and . It follows that (2.5) holds. Observe that (2.2) and (2.5) ensure that
and
Put
Clearly, there exists a subsequence of such that
Combining (2.5), (2.8), (2.12)∼(2.14), Lemma 1.1, and , we get
which is a contradiction. Hence is a Cauchy sequence. Completeness of ensures that there exists satisfying (2.7). Suppose that . Let
Note that (2.2) and (2.7) yield
and
Put . Clearly, there exists a subsequence of such that
In virtue of (2.8), (2.16)∼(2.18), and Lemma 1.1, we conclude that
which together with (2.15) means that
which is impossible. Consequently, is a fixed point of T in X. Suppose that T has another fixed point . Notice that
which together with , (2.8), and means that
which is a contradiction. Consequently, T possesses a unique fixed point . This completes the proof. □
Remark 2.2 The below example is an application of Theorem 2.2.
Example 2.2 Let be endowed with the Euclidean metric , and be defined by
and
Clearly, . For with , we consider the following four cases.
Case 1. Let with . It is easy to verify that
which yields
Case 2. Let with . It is clear that
which gives
Case 3. Let and . Obviously, we have
which implies that
Case 4. Let . It follows that
which means that
That is, (2.8) holds. Thus the conditions of Theorem 2.2 are satisfied. It follows from Theorem 2.2 that T has a unique fixed point and for every .
Similar to the proofs of Theorems 2.1 and 2.2, we have the following results and we omit their proofs.
Theorem 2.3 Let be in and T be a mapping from a complete metric space into itself satisfying
Then T has a unique fixed point such that for each .
Theorem 2.4 Let be in and T be a mapping from a complete metric space into itself satisfying
Then T has a unique fixed point such that for each .
Theorem 2.5 Let be in and T be a mapping from a complete metric space into itself satisfying
Then T has a unique fixed point such that for each .
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Acknowledgements
The authors wish to express their gratitude to the referees for giving valuable comments. This research was supported by the Science Research Foundation of Educational Department of Liaoning Province (L2012380) and Basic Science Research Program through the National Research Foundation of Korea (NRF) funded by the Ministry of Science, ICT & Future Planning (2013R1A1A2057665).
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Liu, Z., Wu, H., Ume, J.S. et al. Some fixed point theorems for mappings satisfying contractive conditions of integral type. Fixed Point Theory Appl 2014, 69 (2014). https://doi.org/10.1186/1687-1812-2014-69
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DOI: https://doi.org/10.1186/1687-1812-2014-69