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- Open Access

# On metric-preserving functions and fixed point theorems

- Prapanpong Pongsriiam
^{1}Email author and - Imchit Termwuttipong
^{2}

**2014**:179

https://doi.org/10.1186/1687-1812-2014-179

© Pongsriiam and Termwuttipong; licensee Springer. 2014

**Received:**31 January 2014**Accepted:**4 August 2014**Published:**1 September 2014

## Abstract

Kirk and Shahzad have recently given, in this journal, fixed point theorems concerning local radial contractions and metric transforms. In this article, we replace the metric transforms by metric-preserving functions. This in turn gives several extensions of the main results given by Kirk and Shahzad. Several examples are given. The fixed point sets of metric transforms and metric-preserving functions are also investigated.

## Keywords

- metric-preserving function
- metric transform
- local radial contraction
- rectifiably pathwise connected space
- uniform local multivalued contraction

## 1 Introduction

The concept of metric transforms is introduced by Blumenthal [1, 2] in 1936 while the concept of metric-preserving functions seems to be introduced by Wilson [3] in 1935 and is investigated in detail by many authors [4–20]. Recently, Petruşel *et al.* [14] have shown the role of equivalent metrics and metric-preserving functions in fixed point theory. In addition, Kirk and Shahzad [21] have given results concerning metric transforms and fixed point theorems. Their main results are as follows:

**Theorem 1** (Kirk and Shahzad [[21], Theorem 2.2])

*Let*$(X,d)$

*be a metric space and*$g:X\to X$.

*Suppose there exist a metric transform*

*ϕ*

*on*

*X*

*and a number*$k\in (0,1)$

*such that the following conditions hold*:

- (a)
*For each*$x\in X$*there exists*${\epsilon}_{x}>0$*such that for every*$u\in X$$d(x,u)<\epsilon \phantom{\rule{1em}{0ex}}\Rightarrow \phantom{\rule{1em}{0ex}}(\varphi \circ d)(g(x),g(u))\le kd(x,u).$ - (b)
*There exists*$c\in (0,1)$*such that for all*$t>0$*sufficiently small*$kt\le \varphi (ct).$

*Then* *g* *is a local radial contraction on* $(X,d)$.

**Theorem 2** (Kirk and Shahzad [[21], Theorem 2.3])

*Suppose*, *in addition to the assumptions in Theorem * 1, *X* *is complete and rectifiably pathwise connected*. *Then* *g* *has a unique fixed point* ${x}_{0}$, *and* ${lim}_{n\to \mathrm{\infty}}{g}^{n}(x)={x}_{0}$ *for each* $x\in X$.

Our purpose is to show that the metric transform *ϕ* in Theorem 1 can be replaced by a metric-preserving function. This in turn gives extensions to the main results given by Kirk and Shahzad in [[21], Theorem 2.2, Theorem 2.3, Theorem 2.8, Theorem 3.4, and Theorem 3.6]. Now let us recall some basic definitions that will be used throughout this article.

**Definition 3**Let $f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$. Then

- (i)
*f*is said to be*a metric transform*if $f(0)=0$,*f*is strictly increasing on $[0,\mathrm{\infty})$, and*f*is concave on $[0,\mathrm{\infty})$, - (ii)
*f*is said to be*a metric-preserving function*if for all metric spaces $(X,d)$, $f\circ d$ is a metric on*X*, - (iii)
*f*is said to be*amenable*if ${f}^{-1}(\{0\})=\{0\}$, - (iv)
*f*is said to be*tightly bounded*if there exists $u>0$ such that $f(x)\in [u,2u]$ for all $x>0$, - (v)
*f*is said to be*subadditive*if $f(a+b)\le f(a)+f(b)$ for all $a,b\in [0,\mathrm{\infty})$.

**Definition 4**Let $(X,d)$ be a metric space and $g:X\to X$. Then

*g*is said to be

*a local radial contraction*if there exists $k\in (0,1)$ such that for each $x\in X$, there exists $\epsilon >0$ such that for every $u\in X$,

**Definition 5**Let $(X,d)$ be a metric space and

*γ*be a path in

*X*, that is, a continuous map $\gamma :[a,b]\to X$. A

*partition*

*Y*of $[a,b]$ is a finite collection of points $Y=\{{y}_{0},\dots ,{y}_{N}\}$ such that $a={y}_{0}\le {y}_{1}\le {y}_{2}\le \cdots \le {y}_{N}=b$. The supremum of the sums

over all the partitions *Y* of $[a,b]$ is called the *length* of *γ*. A path is said to be *rectifiable* if its length is finite. A metric space is said to be *rectifiably pathwise connected* if each two points of *X* can be joined by a rectifiable path.

We will give some auxiliary results in Section 2. Then we will give the results concerning metric-preserving functions, local radial contractions, and uniform local multivalued contractions in Section 3 and Section 4. Finally, we investigate the fixed point sets of metric transforms and metric-preserving functions in Section 5.

## 2 Lemmas

We need to use some properties of metric-preserving functions and some fixed point theorems. We give them in this section for the convenience of the reader. For more details of the metric-preserving functions, we refer the reader to [6, 8, 10].

**Lemma 6**

*Let*$f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$.

*Then*

- (i)
*if**f**is metric preserving*,*then**f**is amenable*, - (ii)
*if**f**is amenable and concave*,*then**f**is metric preserving*.

*Proof* The proof of (i) is easily obtained; see for example, in [[5], Lemma 2.3]. The proof of (ii) is given in [[5], Proposition 1.2] and [[8], p.13]. See also [[4], Proposition 2] and [[6], p.311]. □

**Lemma 7** *Let* $f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$. *If* *f* *is amenable*, *subadditive*, *and increasing*, *then* *f* *is metric preserving*.

*Proof* The proof can be found in [[5], Proposition 1.1], [[6], Proposition 2.3], and [[8], p.9]. □

**Lemma 8** *If* $f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ *is amenable and tightly bounded*, *then* *f* *is metric preserving*.

*Proof* The proof is given in [[5], Proposition 1.3], [[6], Proposition 2.8], and [[8], p.17]. □

**Lemma 9** *If* *f* *is metric preserving and* $0\le a\le 2b$, *then* $f(a)\le 2f(b)$.

*Proof* The proof is given in [[5], Lemma 2.5], and [[8], p.16]. □

*f*, let ${K}_{f}$ denote the set

Recall also that we define $inf\mathrm{\varnothing}=+\mathrm{\infty}$. Then we have the following result.

**Lemma 10**

*Let*$f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$

*be metric preserving*.

*Then*${f}^{\prime}(0)=inf{K}_{f}$.

*In particular*, ${f}^{\prime}(0)$

*always exists in*$\mathbb{R}\cup \{+\mathrm{\infty}\}$

*and*

- (i)
${f}^{\prime}(0)<+\mathrm{\infty}$

*if and only if*${K}_{f}\ne \mathrm{\varnothing}$,*and* - (ii)
${f}^{\prime}(0)=+\mathrm{\infty}$

*if and only if*${K}_{f}=\mathrm{\varnothing}$.

*Proof* The proof can be found in [[4], Theorem 2], [[6], Theorem 4.4], and [[8], pp.37-39]. □

The next lemma is probably well known but we give a proof here for completeness.

**Lemma 11** *If* $f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ *is amenable and concave*, *then the function* $x\mapsto \frac{f(x)}{x}$ *is decreasing on* $(0,\mathrm{\infty})$

*Proof*Let $a,b\in (0,\mathrm{\infty})$ and $a<b$. Since

*f*is concave, we obtain

Therefore $\frac{f(a)}{a}\ge \frac{f(b)}{b}$, as desired. □

**Lemma 12** (Pokorný [16])

*Let* $f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$. *Assume that* *f* *is amenable and there is a periodic function* *g* *such that* $f(x)=x+g(x)$ *for all* $x\ge 0$. *Then* *f* *is metric preserving if and only if* *f* *is increasing and subadditive*.

*Proof* The proof can be found in [[8], p.32] and [[16], Theorem 1]. □

**Lemma 13** (Hu and Kirk [22])

*Let* $(X,d)$ *be a complete metric space for which each two points can be joined by a rectifiable path*, *and suppose* $g:X\to X$ *is a local radial contraction*. *Then* *g* *has a unique fixed point* ${x}_{0}$, *and* ${lim}_{n\to \mathrm{\infty}}{g}^{n}(x)={x}_{0}$ *for each* $x\in X$.

As noted by Kirk and Shahzad [21], an assertion in the proof of Lemma 13 given in [22] was based on a false proposition of Holmes [23]. But Jungck [24] proved that the assertion itself is true. Hence the proof given in [22] with minor changes is true. Kirk and Shahzad [21] apply Tan’s result [25] to extend some of their theorems. We will also apply Tan’s result as well.

**Lemma 14** (Tan [25])

*Let* *X* *be a topological space*, *let* ${x}_{0}\in X$, *and let* $g:X\to X$ *be a mapping for which* $f:={g}^{N}$ *satisfies* ${lim}_{n\to \mathrm{\infty}}{f}^{n}(x)={x}_{0}$ *for each* $x\in X$. *Then* ${lim}_{n\to \mathrm{\infty}}{g}^{n}(x)={x}_{0}$ *for each* $x\in X$. (*Also if* ${x}_{0}$ *is the unique fixed point of* *f*, *it is also the unique fixed point of* *g*.)

We will use Nadler’s result concerning set-valued mappings. So let us recall some more definitions. If $\epsilon >0$ is given, a metric space $(X,d)$ is said to be *ε-chainable* if given $a,b\in X$ there exist ${x}_{1},{x}_{2},\dots ,{x}_{n}\in X$ such that $a={x}_{1}$, $b={x}_{n}$, and $d({x}_{i},{x}_{i+1})<\epsilon $ for all $i\in \{1,2,\dots ,n-1\}$. The result of Nadler that we need is the following.

**Lemma 15** (Nadler [26])

*Let* $(X,d)$ *be a complete* *ε*-*chainable metric space*. *If* $T:X\to \mathcal{CB}(X)$ *is an* $(\epsilon ,k)$-*uniform local multivalued contraction*, *then* *T* *has a fixed point*.

## 3 Local radial contractions and metric-preserving functions

In this section, we will give a generalization of Theorem 1 where the metric transform *ϕ* is replaced by a metric-preserving function. In fact, we obtain a more general result as follows.

**Theorem 16**

*Let*$(X,d)$

*be a metric space and let*$g:X\to X$.

*Assume that there exist*$k\in (0,1)$

*and a metric*-

*preserving function*

*f*

*satisfying the following conditions*:

- (a)
*for each*$x\in X$,*there exists*$\epsilon >0$*such that for every*$u\in X$$d(x,u)<\epsilon \phantom{\rule{1em}{0ex}}\Rightarrow \phantom{\rule{1em}{0ex}}(f\circ d)(g(x),g(u))\le kd(x,u),\phantom{\rule{1em}{0ex}}\mathit{\text{and}}$ - (b)
${f}^{\prime}(0)>k$.

*Then* *g* *is a local radial contraction*.

We know from Lemma 10 that ${f}^{\prime}(0)$ always exists in $\mathbb{R}\cup \{+\mathrm{\infty}\}$. So condition (b) in Theorem 16 makes sense. To prove this theorem, we will first show that *g* is continuous in the following lemma.

**Lemma 17** *Suppose that the assumptions in Theorem * 16 *hold*. *Then the function* *g* *is continuous*.

As a consequence of Theorem 16, we can replace the metric transform *ϕ* in Theorem 1 by a metric-preserving function and obtain an extension of Theorem 1.

**Theorem 18** *With the same assumptions in Theorem * 16 *except that condition* (b) *is replaced by* (b′): *there exists* $c\in (0,1)$ *such that* $f(ct)\ge kt$ *for all* $t>0$ *sufficiently small*. *Then* *g* *is a local radial contraction*.

**Remark 19** As noted by Kirk and Shahzad [[21], Remark 2.5], [[21], Proposition 2.6], metric transforms satisfying condition (b) in Theorem 1 are numerous. Proposition 20, Example 22, and Example 23 (to be given after the proof of Theorem 18) show that the class of metric-preserving functions satisfying condition (b) in Theorem 1 is larger than the class of metric transforms satisfying the same condition. Hence the class of such functions is even more numerous and Theorem 18 is indeed an extension of Theorem 1.

Now let us give the proof of Lemma 17, Theorem 16, and Theorem 18 as follows.

*Proof of Lemma 17*Let $x\in X$ and let $\epsilon >0$. Since $k<{f}^{\prime}(0)={lim}_{y\to {0}^{+}}\frac{f(y)-f(0)}{y-0}={lim}_{y\to {0}^{+}}\frac{f(y)}{y}$, there exists ${\delta}_{1}>0$ such that

*f*is metric preserving, we obtain by Lemma 9, and (3) that for every $b\in [0,\mathrm{\infty})$

Then by (4), $d(g(x),g(u))<\frac{{\delta}_{3}}{2}\le \frac{\epsilon}{2}<\epsilon $. This shows that *g* is continuous, as required. □

*Proof of Theorem 16*Let $c=\frac{1}{2}(\frac{k}{{f}^{\prime}(0)}+1)$ where if ${f}^{\prime}(0)=+\mathrm{\infty}$, we define $\frac{k}{{f}^{\prime}(0)}$ to be zero and $c=\frac{1}{2}(0+1)=\frac{1}{2}$. Then $0\le \frac{k}{{f}^{\prime}(0)}<c<1$. Consider

*g*is a local radial contraction with the contraction constant

*c*, let $x\in X$. By Lemma 17,

*g*is continuous at

*x*. So there exists ${\delta}_{2}>0$ such that for every $u\in X$,

which implies the desired result. This completes the proof. □

*Proof of Theorem 18*By Lemma 10, we know that ${f}^{\prime}(0)$ exists in $\mathbb{R}\cup \{+\mathrm{\infty}\}$ and by Theorem 16, it suffices to show that ${f}^{\prime}(0)>k$. So we can assume further that ${f}^{\prime}(0)$ exists in ℝ. Now ${f}^{\prime}(0)={lim}_{y\to {0}^{+}}\frac{f(y)-f(0)}{y-0}={lim}_{y\to {0}^{+}}\frac{f(y)}{y}$. Since the limits involved in the following calculation exist, we obtain

Therefore ${f}^{\prime}(0)>k$, as desired. □

As noted earlier, we will show that the class of metric-preserving functions and the class of metric-preserving functions satisfying condition (b) in Theorem 1 are, respectively, larger than the class of metric transforms and the class of metric transforms satisfying condition (b) in Theorem 1.

**Proposition 20** *Every metric transform is metric preserving*.

*Proof* Let *f* be a metric transform. Since $f(0)=0$ and *f* is strictly increasing, *f* is amenable. Since *f* is amenable and concave, we obtain by Lemma 6(ii) that *f* is metric preserving. □

**Corollary 21** *Kirk and Shahzad’s result* (*Theorem * 1) *holds*.

*Proof* This follows immediately from Proposition 20 and Theorem 18. □

**Example 22**Let $f,g,h:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ be given by

Since $f(x)\in [1,2]$ for all $x>0$, *f* is tightly bounded. Therefore by Lemma 8, *f* is metric preserving. It is easy to see that *f* is not increasing (and is not concave either). So *f* is not a metric transform. It is easy to see that *g* is amenable and concave, so it is metric preserving, by Lemma 6(ii). In addition, if $c=k=\frac{1}{2}\in (0,1)$, then $g(ct)\ge kt$ for all $t\in [0,1]$. So *g* satisfies condition (b) in Theorem 1. But *g* is not a metric transform because it is not strictly increasing. For *h*, we proved in [[27], Example 14] that *h* is metric preserving. Similar to *g*, the function *h* satisfies the condition (b) in Theorem 1. It is easy to see that *h* is neither strictly increasing nor concave. Therefore *h* is not a metric transform.

We can generate more functions similar to *g* given in Example 22 as follows.

**Example 23**Let $a\ge 1$ and $b>0$. Define ${f}_{a,b}:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ by

Then ${f}_{a,b}$ is amenable and concave. So by Lemma 6(ii), ${f}_{a,b}$ is metric preserving. We also have ${f}_{a,b}^{\prime}(0)=a\ge 1$. So it satisfies condition (b) in Theorem 16. However, ${f}_{a,b}$ is not a metric transform because it is not strictly increasing. In particular, if we let $X=[0,\mathrm{\infty})$, $k=\frac{1}{2}$, $f,g:X\to X$ given by $g(x)=\frac{1}{2}x$ and $f={f}_{1,1}$, then *f* satisfies all the assumptions in Theorem 16.

**Remark 24** Some natural questions concerning the relation of metric transforms, metric-preserving functions, and condition (b) can be answered by Example 22 and Example 23:

Q1: Is there a continuous metric-preserving function which is not a metric transform?

A1: Yes, *g* and *h* given in Example 22 and ${f}_{a,b}$ given in Example 23 are such functions.

Q2: Is there any nowhere continuous metric-preserving function which is not a metric transform?

A2: Yes, *f* given in Example 22 is such a function.

Q3: Is there a nowhere monotone metric-preserving function which is not a metric transform?

A3: Yes, *f* given in Example 22 is such a function.

Q4: Is there a metric-preserving function which is concave and satisfies condition (b) in Theorem 1 but it is not a metric transform?

A4: Yes, *g* given in Example 22 and ${f}_{a,b}$ given in Example 23 are such functions.

Now that we have obtained two extensions of Theorem 1, we give two generalizations of Theorem 2 as follows.

**Theorem 25**

*The following statements hold*:

- (a)
*Suppose*,*in addition to the assumptions in Theorem*16,*X**is complete and rectifiably pathwise connected*.*Then**g**has a unique fixed point*${x}_{0}$,*and*${lim}_{n\to \mathrm{\infty}}{g}^{n}(x)={x}_{0}$*for each*$x\in X$. - (b)
*Suppose*,*in addition to the assumptions in Theorem*18,*X**is complete and rectifiably pathwise connected*.*Then**g**has a unique fixed point*${x}_{0}$,*and*${lim}_{n\to \mathrm{\infty}}{g}^{n}(x)={x}_{0}$*for each*$x\in X$.

*Proof* Part (a) follows immediately from Theorem 16 and Lemma 13. Part (b) follows immediately from Theorem 18 and Lemma 13. □

Finally, we remark that Kirk and Shahzad use Tan’s result (Lemma 14) to extend Theorem 2 further [[21], Theorem 2.3 and Theorem 2.8]. We similarly apply their argument to obtain the following.

**Theorem 26**

*Let*

*X*

*be a metric space which is complete and rectifiably pathwise connected*,

*and suppose*$g:X\to X$

*is a mapping for which*

- (a)
${g}^{N}$

*satisfies the assumptions in Theorem*16*for some*$N\in \mathbb{N}$,*or* - (b)
${g}^{M}$

*satisfies the assumptions in Theorem*18*for some*$M\in \mathbb{N}$.

*Then* *g* *has a unique fixed point* ${x}_{0}$, *and* ${lim}_{n\to \mathrm{\infty}}{g}^{n}(x)={x}_{0}$ *for each* $x\in X$.

*Proof* This follows immediately from Theorem 16, Theorem 18, Lemma 13, and Lemma 14. □

**Conclusion** We have obtained extensions of the main results given by Kirk and Shahzad in [[21], Theorem 2.2, Theorem 2.3, and Theorem 2.8]. We will obtain more results in the next section.

## 4 Set-valued contractions

Kirk and Shahzad [21] also give an analog of Theorem 1 and Theorem 2 for set-valued mappings. Our purpose in this section is to obtain an analog of Theorem 16 and Theorem 18 for set-valued mappings as well. First let us recall some definitions and results concerning set-valued mappings.

*X*. The usual Hausdorff distance on $\mathcal{CB}(X)$ is defined as

where $A,B\in \mathcal{CB}(X)$, $\rho (A,B)={sup}_{x\in A}d(x,B)$, $\rho (B,A)={sup}_{x\in B}d(x,A)$.

**Definition 27**Let $T:X\to \mathcal{CB}(X)$. Then

- (i)
*T*is called*a multivalued contraction mapping*if there exists a constant $k\in (0,1)$ such that $H(Tx,Ty)\le kd(x,y)$ for all $x,y\in X$. - (ii)For $\epsilon >0$ and $k\in (0,1)$,
*T*is called*an*$(\epsilon ,k)$*-uniform local multivalued contraction*if for every $x,y\in X$$d(x,y)<\epsilon \phantom{\rule{1em}{0ex}}\Rightarrow \phantom{\rule{1em}{0ex}}H(Tx,Ty)\le kd(x,y).$ - (iii)
A point $x\in X$ is said to be

*a fixed point of**T*if $x\in Tx$.

Kirk and Shahzad’s results on set-valued mappings which will be extended are as follows.

**Theorem 28** (Kirk and Shahzad [[21], Theorem 3.4])

*Let*$(X,d)$

*be a metric space and*$T:X\to \mathcal{CB}(X)$.

*Suppose there exist a metric transform*

*ϕ*

*and*$k\in (0,1)$

*such that the following conditions hold*:

- (a)
*For each*$x,y\in X$, $\varphi (H(Tx,Ty))\le kd(x,y)$. - (b)
*There exists*$c\in (0,1)$*such that for*$t>0$*sufficiently small*, $kt\le \varphi (ct)$.

*Then for* $\epsilon >0$ *sufficiently small*, *T* *is an* $(\epsilon ,c)$-*uniform local multivalued contraction on* $(X,d)$.

**Theorem 29** (Kirk and Shahzad [[21], Theorem 3.6])

*If*, *in addition to the assumptions of Theorem * 28, *X* *is complete and connected*, *then* *T* *has a fixed point*.

Our aim is to replace the metric transform *ϕ* in Theorem 28 by a metric-preserving function. We obtain the following theorem.

**Theorem 30**

*Let*$(X,d)$

*be a metric space and*$T:X\to \mathcal{CB}(X)$.

*Suppose there exist a metric*-

*preserving function*

*f*

*and*$k\in (0,1)$

*such that the following conditions hold*:

- (a)
*For each*$x,y\in X$, $f(H(Tx,Ty))\le kd(x,y)$. - (b)
${f}^{\prime}(0)>k$.

*Then for* $\epsilon >0$ *sufficiently small*, *T* *is an* $(\epsilon ,c)$-*uniform local multivalued contraction on* $(X,d)$.

**Corollary 31** *With the same assumptions in Theorem * 30 *except that condition* (b) *is replaced by* (b′): *there exists* $c\in (0,1)$ *such that for* $t>0$ *sufficiently small*, $kt\le f(ct)$. *Then for* $\epsilon >0$ *sufficiently small*, *T* *is an* $(\epsilon ,c)$-*uniform local multivalued contraction on* $(X,d)$.

**Theorem 32** *If*, *in addition to the assumptions of Theorem * 30 *or Corollary * 31, *X* *is complete and* *ε*-*chainable*, *then* *T* *has a fixed point*. *In particular*, *if* *X* *is complete and connected*, *then* *T* *has a fixed point*.

The proof of these results are similar to those in Section 3.

*Proof of Theorem 30*We define $c=\frac{1}{2}(\frac{k}{{f}^{\prime}(0)}+1)$ as in the proof of Theorem 16. Then $0\le \frac{k}{{f}^{\prime}(0)}<c<1$ and there exists ${\delta}_{1}>0$ such that for every $z\in [0,\mathrm{\infty})$

*T*is an $(\epsilon ,c)$-uniform local multivalued contraction for $\epsilon >0$ sufficiently small, we let $0<\epsilon <\frac{{\delta}_{1}}{2}$ and let $x,y\in X$ be such that $d(x,y)<\epsilon $. By Lemma 9 and (10), we have for every $b\in [0,\mathrm{\infty})$

where the first inequality is obtained by applying (12) and (10) and the last inequality is merely the condition (a). This implies $H(Tx,Ty)\le cd(x,y)$, as desired. □

*Proof of Corollary 31* We can imitate the proof of Theorem 18 to obtain ${f}^{\prime}(0)>k$. So Corollary 31 follows immediately from Theorem 30. □

*Proof of Theorem 32* This follows from Theorem 30, Corollary 31, and Lemma 15. The other part follows from the fact that a connected metric space is *ε*-chainable for every $\epsilon >0$. □

**Conclusion** We replace the metric transform *ϕ* by a metric-preserving function. Therefore we obtain theorems more general than those of Kirk and Shahzad [[21], Theorem 2.2, Theorem 2.3, Theorem 2.8, Theorem 3.4, and Theorem 3.6].

## 5 Fixed point set of metric transforms and metric-preserving functions

Recall that for a function $f:X\to X$, we denote by Fix*f* the set of all fixed points of *f*. We begin this section with the following lemma.

**Lemma 33** *Let* $f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ *be a metric transform*. *If* $0<a<b$, $f(a)=a$, *and* $f(b)=b$, *then* $[a,b]\subseteq Fixf$.

*Proof* Since *f* is amenable and concave, the function $x\mapsto \frac{f(x)}{x}$ is decreasing on $(0,\mathrm{\infty})$ by Lemma 11. So if $a\le x\le b$, then $1=\frac{f(a)}{a}\ge \frac{f(x)}{x}\ge \frac{f(b)}{b}=1$, which implies $f(x)=x$. This shows that $[a,b]\subseteq Fixf$. □

**Lemma 34** *If* $f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ *is a metric transform*, *then* Fix*f* *is a closed subset of* $[0,\mathrm{\infty})$.

*Proof*Let $({a}_{n})$ be a sequence in Fix

*f*and ${a}_{n}\to a$. If $a=0$ or $a={a}_{n}$ for some $n\in \mathbb{N}$, then $a\in Fixf$ and we are done. So assume that $a>0$ and $a\ne {a}_{n}$ for any $n\in \mathbb{N}$. Since $a>0$ and ${a}_{n}\to a$, ${a}_{n}>0$ for all large

*n*. By passing to the subsequence, we can assume that ${a}_{n}>0$ for every $n\in \mathbb{N}$. It is well known that every sequence of real numbers has a monotone subsequence (see

*e.g.*[[28], p.62]). By passing to the subsequence again, we can assume that $({a}_{n})$ is monotone. Now suppose that $({a}_{n})$ is increasing. Then by Lemma 33,

*f*is increasing and ${a}_{n}<a$, ${a}_{n}=f({a}_{n})\le f(a)$ for every $n\in \mathbb{N}$. Since ${a}_{n}\le f(a)$ for every $n\in \mathbb{N}$ and ${a}_{n}\to a$, we have

From (13) and (14), we obtain $f(a)=a$, as required. The case where $({a}_{n})$ is decreasing can be proved similarly. This completes the proof. □

**Lemma 35** *Let* $f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ *be a metric transform*. *Then* $Fixf=[0,\mathrm{\infty})$ *if and only if* $supFixf=+\mathrm{\infty}$.

*Proof*It is enough to show that $supFixf=+\mathrm{\infty}$ implies $(0,\mathrm{\infty})\subseteq Fixf$. So suppose that $supFixf=+\mathrm{\infty}$ but there exists $x\in (0,\mathrm{\infty})$ such that $f(x)\ne x$. Since $supFixf=+\mathrm{\infty}$, there exists $a>x$ such that $f(a)=a$. Similarly, there exists $b>a$ such that $f(b)=b$. Since

*f*is amenable and concave, we obtain by Lemma 11

*f*, we obtain

a contradiction. This completes the proof. □

**Theorem 36** *If* $a>0$, *then each set of the form* $\{0\}$, $\{0,a\}$, $[0,a]$, *and* $[0,\mathrm{\infty})$ *is a fixed point set of a metric transform*. *Conversely*, *if* *f* *is a metric transform*, *then* $Fixf=\{0\},\{0,a\},[0,a]$, *or* $[0,\mathrm{\infty})$ *for some* $a\in (0,\mathrm{\infty})$.

*Proof*Define ${f}_{1},{f}_{2},{f}_{3},{f}_{4}:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ by

It is easy to verify that the functions ${f}_{1}$, ${f}_{2}$, ${f}_{3}$, ${f}_{4}$ are metric transforms and $Fix{f}_{1}=\{0\}$, $Fix{f}_{2}=\{0,a\}$, $Fix{f}_{3}=[0,\mathrm{\infty})$, and $Fix{f}_{4}=[0,a]$. This proves the first part.

*f*be a metric transform such that $Fixf\ne \{0\}$ and $Fixf\ne [0,\mathrm{\infty})$. We let $a=supFixf$ and assert that $Fixf=\{0,a\}$ or $[0,a]$. Note that since $Fixf\ne \{0\}$, $a>0$. It is obtained by Lemma 35 that $a<+\mathrm{\infty}$. Now apply Lemma 34 to get $a\in Fixf$. Therefore $\{0,a\}\subseteq Fixf$. By the definition of

*a*, we see that $x\notin Fixf$ for every $x>a$. Now if $x\notin Fixf$ for every $0<x<a$, then $Fixf=\{0,a\}$ and we are done. So assume that there exists $0<x<a$ such that $x\in Fixf$. We will show that $Fixf=[0,a]$. Since $a=supFixf$, it is obvious that $Fixf\subseteq [0,a]$. Suppose for a contradiction that there exists $0<y<a$ such that $f(y)\ne y$. Since $0<x<a$ and $x,a\in Fixf$, we obtain by Lemma 33 that $y\notin [x,a]$. So $y<x$. By Lemma 11 we have

*f*, we obtain

a contradiction. This completes the proof. □

Since every metric transform is metric preserving, we immediately obtain the result that each set of the form $\{0\}$, $\{0,a\}$, $[0,a]$, and $[0,\mathrm{\infty})$ is a fixed point set of a metric-preserving function. However, there is a metric-preserving function *f* where Fix*f* is not of this form. Let us show this more precisely.

**Corollary 37** *If* $a>0$, *then each set of the form* $\{0\}$, $\{0,a\}$, $[0,a]$, *and* $[0,\mathrm{\infty})$ *is a fixed point of a metric*-*preserving function*.

*Proof* This follows immediately from Theorem 36 and Proposition 20. □

**Example 38**Let $f,g,h:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ be given by

(Recall that $\lceil x\rceil $ is the smallest integer which is larger than or equal to *x*.) It is easy to verify that *f* is amenable, increasing, and subadditive. So by Lemma 7, *f* is metric preserving. Since *g* and *h* are amenable and tightly bounded, we obtain by Lemma 8 that *g* and *h* are metric-preserving. It is easy to see that $Fixf=\mathbb{N}\cup \{0\}$, $Fixg=\{0,1,\sqrt{2}\}$, and $Fixh=\{0\}\cup (\mathbb{Q}\cap [1,2])$.

By generating a function similar to *h* we obtain a more general result as follows.

**Proposition 39** *Let* $A\subseteq [u,2u]$ *for some* $u>0$. *Then* $A\cup \{0\}$ *is a fixed point set of a metric*-*preserving function*.

*Proof*We define $f:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ by

and if $u\notin A$, then define $f(u)=2u$. Then *f* is amenable and tightly bounded. Therefore, by Lemma 8, *f* is metric preserving. It is easy to see that $Fixf=A\cup \{0\}$. This completes the proof. □

From Example 38 and Proposition 39, we see that the fixed point set of a metric-preserving function may not be of the form $\{0\}$, $\{0,a\}$, $[0,a]$, and $[0,\mathrm{\infty})$. Other natural questions and answers are the following:

Q1: Is there a metric-preserving function which does not satisfy the result in Lemma 33?

A1: Every function given in Example 38 is such a function.

Q2: Is there a metric-preserving function which does not satisfy the result in Lemma 34?

A2: The function *h* given in Example 38 and the function *f* given in Proposition 39 (with a suitable set *A*) are such functions.

Q3: Is there a metric-preserving function which does not satisfy the result in Lemma 35?

A3: The function *f* given in Example 38 is such a function.

We see that the fixed point sets of metric-preserving functions are quite difficult to be completely characterized. We leave this problem to the interested reader. Now we end this article by giving continuous metric-preserving functions which do not satisfy the results in Lemma 33 and Lemma 35.

**Example 40**Let $f,g:[0,\mathrm{\infty})\to [0,\mathrm{\infty})$ be given by $f(x)=\lfloor x\rfloor +\sqrt{x-\lfloor x\rfloor}$ and $g(x)=x+|sinx|$. (Recall that $\lfloor x\rfloor $ is the largest integer which is less than or equal to

*x*.) We will use Lemma 12 to show that

*f*and

*g*are metric-preserving. First, the function $x\mapsto |sinx|$ is periodic with period

*π*.

So the function $x\mapsto |sinx|$ is also subadditive. From this, we easily see that *g* satisfies the condition in Lemma 12. So *g* is metric preserving. It is not difficult to verify that *f* is also satisfies the assumption in Lemma 12 and we will leave the details to the reader. It is also easy to see that $Fixf=\mathbb{N}\cup \{0\}$ and $Fixg=\{n\pi \mid n\in \mathbb{N}\cup \{0\}\}$. So *f* and *g* are continuous metric preserving functions of which fixed point sets do not satisfy the results in Lemma 33 and Lemma 35.

## Declarations

### Acknowledgements

The first author would like to thank The Thailand Research Fund for financial support under the contract number TRG5680052. Both authors also would like to thank Professor IA Rus for sending them his article on the role of equivalent metrics and metric-preserving functions in fixed point theory which helps improve the presentation of this article.

## Authors’ Affiliations

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