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Coupled best proximity points in ordered metric spaces
Fixed Point Theory and Applications volume 2014, Article number: 107 (2014)
Abstract
In this paper, we prove the existence and uniqueness of a coupled best proximity point for mappings satisfying the proximally coupled contraction condition in a complete ordered metric space. Further, our result provides an extension of a result due to Luong and Thuan (Comput. Math. Appl. 62(11):4238-4248, 2011; Nonlinear Anal. 74:983-992, 2011).
MSC:41A65, 90C30, 47H10.
1 Introduction and preliminaries
Let A be a nonempty subset of a metric space . A mapping has a fixed point in A if the fixed point equation has at least one solution. That is, is a fixed point of T if . If the fixed point equation does not possess a solution, then for all . In such a situation, it is our aim to find an element such that is minimum in some sense. The best approximation theory and best proximity pair theorems are studied in this direction. Here we state the following well-known best approximation theorem due to Ky Fan [1].
Theorem 1.1 ([1])
Let A be a nonempty compact convex subset of a normed linear space X and be a continuous function. Then there exists such that .
Such an element in Theorem 1.1 is called a best approximant of T in A. Note that if is a best approximant, then need not be the optimum. Best proximity point theorems have been explored to find sufficient conditions so that the minimization problem has at least one solution. To have a concrete lower bound, let us consider two nonempty subsets A, B of a metric space X and a mapping . The natural question is whether one can find an element such that . Since , the optimal solution to the problem of minimizing the real valued function over the domain A of the mapping T will be the one for which the value is attained. A point is called a best proximity point of T if . Note that if , then the best proximity point is nothing but a fixed point of T. Also, best proximity point theory in ordered metric spaces was first studied in [2].
The existence and convergence of best proximity points is an interesting topic of optimization theory which recently attracted the attention of many authors [3–13]. Also one can find the existence of best proximity point in the setting of partially order metric space in [14–17].
On the other hand, Bhaskar and Lakshmikantham have introduced the concept called mixed monotone mapping and proved coupled fixed point theorems for mappings satisfying the mixed monotone property, which is used to investigate a large class of problems, and they discussed the existence and uniqueness of a solution for a periodic boundary value problem. One can find the existence of coupled fixed points in the setting of partially order metric space in [18–24].
Now we recall the definition of a coupled fixed point which was introduced by Sintunavarat and Kumam in [16]. Let X be a nonempty set and be a given mapping. An element is called a coupled fixed point of the mapping F if and .
The authors mentioned above also introduced the notion of mixed monotone mapping. If is a partially ordered set, the mapping F is said to have the mixed monotone property if
and
In [25] Luong and Thuan obtained a more general result. For this, let Φ denote all functions which satisfy
-
(i)
ϕ is continuous and nondecreasing,
-
(ii)
if and only if ,
-
(iii)
, .
Again, let Ψ denote all functions which satisfy for all and .
The main theoretical results of Luong and Thuan, in [25] is the following.
Theorem 1.2 ([25])
Let be a partially ordered set and suppose there is a metric d on X such that is a complete metric space. Let be a mapping having the mixed monotone property on X such that
for all with and , where and . If there exist such that and . Suppose either
-
(a)
F is continuous or
-
(b)
X has the following property:
-
(i)
if a nondecreasing sequence , then for all n,
-
(ii)
if a nonincreasing sequence , then for all n,
then there exist such that and .
Motivated by the above theorems, we introduce the concept of the proximal mixed monotone property and of a proximally coupled weak contraction on A. We also explore the existence and uniqueness of coupled best proximity points in the setting of partially ordered metric spaces. Further, we attempt to give the generalization of Theorem 1.2.
Let X be a nonempty set such that is a metric space. Unless otherwise specified, it is assumed throughout this section that A and B are nonempty subsets of the metric space ; the following notions are used subsequently:
In [9], the authors discussed sufficient conditions which guarantee the nonemptiness of and . Also, in [7], the authors proved that is contained in the boundary of A. Moreover, the authors proved that is contained in the boundary of A in the setting of normed linear spaces.
Definition 1.3 Let be a partially ordered metric space and A, B are nonempty subsets of X. A mapping is said to have proximal mixed monotone property if is proximally nondecreasing in x and is proximally nonincreasing in y, that is, for all
and
where .
One can see that, if in the above definition, the notion of the proximal mixed monotone property reduces to that of the mixed monotone property.
Lemma 1.4 Let be a partially ordered metric space and A, B are nonempty subsets of X. Assume is nonempty. A mapping has the proximal mixed monotone property with whenever , , , , in such that
Proof By hypothesis , therefore . Hence there exists such that
Using F is proximal mixed monotone (in particular F is proximally nondecreasing in x) to (2) and (3), we get
Analogously, using the fact that F is proximal mixed monotone (in particular F is proximally nonincreasing in y) to (2) and (3), we get
From (4) and (5), one can conclude the . Hence the proof. □
Lemma 1.5 Let be a partially ordered metric space and A, B are nonempty subsets of X. Assume is nonempty. A mapping has proximal mixed monotone property with whenever , , , , in such that
Proof The proof is the same as Lemma 1.4. □
Definition 1.6 Let be a partially ordered metric space and A, B are nonempty subsets of X. A mapping is said to be proximally coupled weak contraction on A, whenever
where .
One can see that, if in the above definition, the notion of a proximally coupled weak contraction on A reduces to that of a coupled weak contraction. Let us recall the notion of the P-property: The pair of nonempty subsets of a metric space with . is said to have the P-property if and only if
where and . It is interesting to note that if the pair considered in the above definition has the P-property, then the mapping F in Theorem 1.2 satisfies the inequality (1).
2 Coupled best proximity point theorems
Let be a partially ordered complete metric space endowed with the product space with the following partial order:
Theorem 2.1 Let be a partially ordered complete metric space. Let A and B be nonempty closed subsets of the metric space such that . Let satisfy the following conditions.
-
(i)
F is a continuous proximally coupled weak contraction on A having the proximal mixed monotone property on A such that .
-
(ii)
There exist elements and in such that
Then there exists such that and .
Proof By hypothesis there exist elements and in such that
Because of the fact that , there exists an element in such that
Hence from Lemma 1.4 and Lemma 1.5, we obtain and .
Continuing this process, we can construct the sequences and in such that
and
Then , and also we have , , . Now using the fact that F is a proximally coupled weak contraction on A we get
Similarly
Adding (11) and (12), we get
By the property (iii) of ϕ we have
From (13) and (14), we get
Using the fact that ϕ is nondecreasing, we get
Set ; then the sequence is decreasing. Therefore, there is some such that
We shall show that . Suppose, to the contrary, that . Then taking the limit as on both sides of (15) and having in mind that we assume for all and ϕ is continuous, we have
a contradiction. Thus , that is,
Now we prove that and are Cauchy sequences. Assume that at least one of the sequences or is not a Cauchy sequence. This implies that or , and, consequently,
Then there exists for which we can find subsequences , of and , of such that is the smallest index for which ,
This means that
Using (19), (20), and the triangle inequality, we have
Letting and using (18), we obtain
By the triangle inequality
Using the property of ϕ, we obtain
Since and , using the fact that F is a proximally coupled weak contraction on A we get
Similarly, we also have
From (22)-(24), we have
Letting and using (18) and (21), we have
a contradiction. This shows that and are Cauchy sequences. Since A is a closed subset of a complete metric space X, these sequences have limits. Thus, there exist such that and . Therefore in . Since F is continuous, we have and .
Hence the continuity of the metric function d implies that and . But from (9) and (10) we see that the sequences and are constant sequences with the value . Therefore, and . This completes the proof of the theorem. □
Corollary 2.1 Let be a partially ordered complete metric space. Let A be nonempty closed subsets of the metric space . Let satisfy the following conditions.
-
(i)
F is continuous having the proximal mixed monotone property and proximally coupled weak contraction on A.
-
(ii)
There exist and in such that with and with .
Then there exists such that and .
In what follows we prove that Theorem 2.1 is still valid for F not necessarily continuous, assuming the following hypotheses in A. A has the property that
Theorem 2.2 Assume the conditions (25), (26) and is closed in X instead of continuity of F in Theorem 2.1, then the conclusion of Theorem 2.1 holds.
Proof Following the proof of Theorem 2.1, there exist sequences and in A satisfying the following conditions:
Moreover, converges to x and converges to y in A. From (25) and (26), we get and . Note that the sequences and are in and is closed. Therefore, . Since , there exist and in . Therefore, there exists such that
Since and . By using the fact that F is a proximally coupled weak contraction on A for (27) and (29), and also for (30) and (28), we get
Since and , by taking the limit on the above two inequalities, we get and . Hence, from (29) and (30), we get and . □
Corollary 2.2 Assume the conditions (25) and (26) instead of continuity of F in Corollary 2.1, then the conclusion of Corollary 2.1 holds.
Now, we present an example where it can be appreciated that the hypotheses in Theorem 2.1 and Theorem 2.2 do not guarantee uniqueness of the coupled best proximity point.
Example 2.3 Let and consider the usual order and .
Thus, is a partially ordered set. Besides, is a complete metric space considering the Euclidean metric. Let and be a closed subset of X. Then , and . Let be defined as . Then, it can be seen that F is continuous such that . The only comparable pairs of points in A are for , hence the proximal mixed monotone property and the proximally coupled weak contraction on A are satisfied trivially.
It can be shown that the other hypotheses of the theorem are also satisfied. However, F has three coupled best proximity points, , , and .
One can prove that the coupled best proximity point is in fact unique, provided that the product space endowed with the partial order mentioned earlier has the following property:
It is known that this condition is equivalent to the following.
For every pair of , there exists in
Theorem 2.4 In addition to the hypothesis of Theorem 2.1 (resp. Theorem 2.2), suppose that for any two elements and in ,
then F has a unique coupled best proximity point.
Proof From Theorem 2.1 (resp. Theorem 2.2), the set of coupled best proximity points of F is nonempty. Suppose that there exist and in which are coupled best proximity points. That is,
We distinguish two cases.
Case 1: Suppose is comparable. Let is comparable to with respect to the ordering in . Applying the fact that F is a proximally coupled weak contraction on A to and , we get
Similarly, one can prove that
Adding (34) and (35), we get
By the property (iii) of ϕ, we have
From (36) and (37), we have
this implies that , and using the property of ψ, we get , hence and .
Case 2: Suppose is not comparable. Let be not comparable to , then there exists which is comparable to and .
Since , there exists such that and . Without loss of generality assume that (i.e., and ). Note that implies that . From Lemma 1.4 and Lemma 1.5, we get
and
From the above two inequalities, we obtain . Continuing this process, we get sequences and such that and with , . By using the fact that F is a proximally coupled weak contraction on A, we get
Similarly, we can prove that
Adding (39) and (40), we obtain
But , hence
Using the fact that ϕ is nondecreasing, we get
That is, the sequence is decreasing. Therefore, there exists such that
We shall show that . Suppose, to the contrary, that . Taking the limit as in (42), we have
a contradiction. Thus, , that is,
so that and . Analogously, one can prove that and .
Therefore, and . Hence the proof. □
The following result, due to Theorem 2.4 in Luong and Thuan [25] follows by taking .
Corollary 2.3 In addition to the hypothesis of Corollary 2.1 (resp. Corollary 2.2), suppose that for any two elements and in ,
then F has a unique coupled fixed point.
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Acknowledgements
The first author was supported by the Higher Education Research Promotion and National Research University Project of Thailand, Office of the Higher Education Commission (NRU2557). Moreover, Kanokwan Sitthithakerngkiet would like to thank the King Mongkut’s University of Technology North Bangkok for financial support.
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The main idea of this paper was proposed by PK, VP, MM and KS prepared the manuscript initially and performed all the steps of the proofs in this research. All authors read and approved the final manuscript.
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Kumam, P., Pragadeeswarar, V., Marudai, M. et al. Coupled best proximity points in ordered metric spaces. Fixed Point Theory Appl 2014, 107 (2014). https://doi.org/10.1186/1687-1812-2014-107
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DOI: https://doi.org/10.1186/1687-1812-2014-107