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Global bifurcation results for general Laplacian problems
Fixed Point Theory and Applications volume 2012, Article number: 7 (2012)
Abstract
In this article, we consider the global bifurcation result and existence of solutions for the following general Laplacian problem,
where f : [0,1] × ℝ × ℝ → ℝ is continuous and ϕ, ψ : ℝ → ℝ are odd increasing homeomorphisms of ℝ, when ϕ, ψ satisfy the asymptotic homogeneity conditions.
1 Introduction
In this article, we consider the following general Laplacian problem,
where f : [0,1] × ℝ × ℝ → ℝ is continuous with f(t,u,0) = 0 and ϕ, ψ : ℝ → ℝ are odd increasing homeomorphisms of ℝ with ϕ(0) = ψ(0) = 0. We consider the following conditions;
(Φ1) , for all σ ∈ ℝ+, for some p > 1.
(Φ2) , for all σ ∈ ℝ+, for some q > 1.
(F1) f(t,u,λ) = o(|ψ(u)|) near zero, uniformly for t and λ in bounded intervals.
(F2) f(t,u,λ) = o(|ψ(u)|) near infinity, uniformly for t and λ in bounded intervals.
(F3) uf(t,u,λ) ≥ 0.
We note that ϕ r (t) = |t|r-2t, r > 1 are special cases of ϕ and ψ. We first prove following global bifurcation result.
Theorem 1.1. Assume (Φ1), (Φ2), (F1), (F2) and (F3). Then for any j ∈ ℕ, there exists a connected component of the set of nontrivial solutions for (P) connecting (0, λ j (p)) to (∞, λ j (q)) such that implies that u has exactly j - 1 simple zeros in (0, 1), where λ j (r) is the j-th eigenvalue of (ϕ r (u'(t)))' + λϕ r (u(t)) = 0 and u(0) = u(1) = 0.
By the aid of this theorem, we can prove the following existence result of solutions.
Theorem 1.2. Consider problem
where g : [0,1] × ℝ × ℝ → ℝ is continuous and ϕ is odd increasing homeomorphism of ℝ, which satisfy (Φ1) and (Φ2) with ϕ = ψ. Also ug(t, u) ≥ 0 and there exist positive integers k, n with k ≤ n such that uniformly in t ∈ [0,1]. Then for each integer j with k ≤ j ≤ n, problem (A) has a solution with exactly j - 1 simple zeros in (0, 1). Thus, (A) possesses at least n-k + 1 nontrivial solutions.
In [1], the authors studied the existence of solutions and global bifurcation results for
The main purpose of this article is to derive the same result for N = 1 case with Dirichlet boundary condition which was not considered in [1].
For p-Laplacian problems, i.e., ϕ = ψ = ϕp, many authors have studied for the existence and multiplicity of nontrivial solutions [2–6]. In [2, 5, 6], the authors used fixed point theory or topological degree argument. Also global bifurcation theory was mainly employed in [3, 4]. Moreover, there are some studies related to general Laplacian problems [3, 7, 8], but most of them are about ϕ = ψ case. In [3], the authors proved some results under several kinds of boundary conditions and in [7], the authors considered a system of general Laplacian problems. In [8], the author studied global continuation result for the singular problem. In this paper, we mainly study the global bifurcation phenomenon for general Laplacian problem (P) and prove the existence and multiplicity result for (A).
This article is organized as follows: In Section 2, we set up the equivalent integral operator of (P) and compute the degree of this operator. In Section 3, we verify the existence of global bifurcation having bifurcation points at zero and infinity simultaneously. In Section 4, we introduce an existence result as an application of the previous result and give some examples.
2 Degree estimate
Let us consider problem (P) with f ≡ 0, i.e.,
We introduce the equivalent integral operator of problem . For this, we consider the following problem
where h ∈ L1(0, 1). Here, a function u is called a solution of (AP) if with ϕ(u') absolutely continuous which satisfies (AP). We note that (AP) is equivalently written as
where a : L1(0, 1) → ℝ is a continuous function which sends bounded sets of L1 into bounded sets of ℝ and satisfying
It is known that is continuous and maps equi-integrable sets of L1(0, 1) into relatively compact sets of . One may refer Manásevich-Mawhin [4, 3] and Garcia-Huidobro-Manásevich-Ward [7] for more details. If we define the operator by
then is equivalently written as . Now let us consider p-Laplacian problem
By the similar argument, we can also get the equivalent integral operator of problem (E p ), which is known by Garcia-Huidobro-Manásevich-Schmitt [1]. Let us define by
where a p : L1(0, 1) → ℝ is a continuous function which sends bounded sets of L1 into bounded sets of ℝ and satisfying
Note that a p has homogineity property, i.e., a p (λt) = λa p (t). Problem (E p ) can be equiva-lently written as . Obviously, and are completely continuous.
The main purpose of this section is to compute the Leray-Schauder degree of . Following Lemma is for the property of ϕ and ψ with asymptotic homogeneity condition (Φ1) and (Φ2), which is very useful for our analysis. The proof can be modified from Proposition 4.1 in [9].
Lemma 2.1. Assume that ϕ, ψ are odd increasing homeomorphisms of ℝ which satisfy (Φ1) and (Φ2). Then, we have
and
To compute the degree, we will make use of the following well-known fact [10].
Lemma 2.2. If λ is not an eigenvalue of (E p ), p > 1 and r > 0, then
Now, let us compute when λ is not an eigenvalue of (E p ).
Theorem 2.3. Assume that ϕ, ψ are odd increasing homeomorphisms of ℝ which satisfy (Φ1) and (Φ2). then,
-
(i)
The Leray-Schauder degree of is defined for B(0, ε), for all sufficiently small ε.
Moreover, we have
(ii) The Leray-Schauder degree of is defined for B(0, M), for all sufficiently large M, and
Proof: We give the proof for assertion (i). Proof for the latter case is similar. Define by . We claim that the Leray-Schauder degree for I - Tλ(·, τ) is defined for B(0, ε) in for all small ε. Indeed, suppose there exist sequences {u n }, {τ n } and {ε n } with ε n → 0 and ∥u n ∥0 = ε n such that un = Tλ(u n , τ n ), i.e.,
Setting , we have ∥v n ∥0 = 1,
and
Now, we show that is uniformly bounded. Since ∥v n ∥0 = 1, . Moreover, there exists C1 such that a p (-λϕ p (v n )) ≤ C1. These results imply the uniform boundedness of . Let
and
Then d n ∈ C[0, 1], and
Since , we have
Otherwise, (or > 0). Now, we show that is bounded. Indeed, suppose that it is not true, i.e., as n → ∞. Then, for arbitrary A > 0, there exists N0 ∈ ℕ such that , for all n > N0. This implies that for all n > N0. However, as n → ∞. This is a contradiction. Thus by the above inequality, we get
for some C2 > 0. Therefore, is uniformly bounded. By the Arzela-Ascoli Theorem, {v n } has a uniformly convergent subsequence in C[0,1] relabeled as the original sequence so let limn→ ∞, v n = v. Now, we claim that q n (t) → q(t), where
Clearly,
Since has a convergent subsequence. Without loss of generality, we say that the sequence converges to d. Also by the facts that as n → ∞, ϕ(ε n ) → 0 and (i) of Lemma 2.1, we obtain
Since ,
Thus and by the definition of a p , d = a p (- λϕ p (v)). Therefore, we can easily see that
and
Consequently, v is a solution of (E p ). Since , v ≡ 0 and this fact yields a contradiction. By the properties of the Leray-Schauder degree, we get
and the proof is completed by Lemma 2.2.
3 Existence of unbounded continuum
We begin with this section recalling what we mean by bifurcation at zero and at infinity. Let X be a Banach space with norm ∥ · ∥, and let be a completely continuous operator, where I is some real interval. Consider the equation
Definition 3.1. Suppose that for all λ in I, and that . We say that is a bifurcation point of (9) at zero if in any neighborhood of in X × I, there is a nontrivial solution of (9). Or equivalently, if there exist sequences {x n ≠ 0} and {λ n } with and such that (x n , λ n ) satisfies (9) for each n ∈ ℕ.
Definition 3.2. We say that is a bifurcation point of (9) at infinity if in any neigh-borhood of in X × I, there is a nontrivial solution of (9). Equivalently, if there exist sequences {x n ≠ 0} and {λ n } with and such that (x n , λ n ) satisfies (9) for each n ∈ ℕ.
Let u be a solution of problem (P). Define by
We note that (P) is written as . It is clear that is a completely continuous operator.
Lemma 3.3. (i) Assume (Φ1) and (F1). if is a bifurcation point of (P), then for some p ∈ ℕ.
(ii) Assume (Φ2) and (F2). if is a bifurcation point of (P), then for some q ∈ ℕ.
Proof: We prove assertion (i). Suppose that is a bifurcation point of (P). Then there exists a sequence {(u n , λ n )} in with and such that (u n , λ n ) satisfies for each n ∈ ℕ. Equivalently, (u n , λ n ) satisfies
with .
Let ε n = ∥u n ∥0 and . Then
and
Now, define . Since f(t, u, λ) = o(|ψ(u)|) near zero, uniformly for t and λ, for some constants K1 and K2.
Since , we have
Otherwise, or < 0. Now, let us verify that is bounded. If as n → ∞ then for arbitrary A > 0, there exists N0 ∈ ℕ such that
This implies that , for all n ≥ N0. This is impossible. Thus
Consequently, is uniformly bounded and by the Arzela-Ascoli Theorem, {v n } has a uniformly convergent subsequence in C[0,1]. Let v n → v in C[0,1]. Now claim that
Clearly,
where .
Since is bounded, considering a subsequence if necessary, we may assume that sequence converges to d as n → ∞. This implies that
and thus . Since v n (1) = 0 for all and v is a solution of (E p ). Consequently, must be an eigenvalue of the p-Laplacian operator.
The converse of first part of Theorem 3.3 is true in our problem.
Lemma 3.4. Assume (Φ1) and (F1). If μ is an eigenvalue of (E p ), then (0, μ) is a bifurcation point.
Proof: Suppose that (0, μ) is not a bifurcation point of (P). Then there is a neighborhood of (0, μ) containing no nontrivial solutions of (P). In particular, we may choose an ε-ball B ε such that there are no solutions of (P) on ∂B ε × [μ - ε, μ + ε] and μ is the only eigenvalue of (E p ) on [μ - ε, μ + ε]. Let . Then deg(Φ(·, λ), B(0,ε), 0) is well-defined for λ with |λ-μ| ≤ ε. Moreover, from the homotopy invariance theorem,
Now, we claim that
where . Define by
We know that and are completely continuous. To apply the homotopy invariance theorem, we need to show that 0 ∉ u - Hμ-ε(u, τ)(∂B ε ) to guarantee well-definedness of deg(I-Hμ-ε(∙, τ), B(0, ε), 0). Suppose that this is not the case, then there exist sequences {u n }, {τ n } and {ε n } with ε n → 0 and ||u n ||0 = ε n such that u n = Hμ-ε(u n , τ n ), i.e.,
Setting , we have that ∥v n ∥0 = 1 and
Hence, we Obtain that
and we see that is uniformly bounded. Therefore, by the Arzela-Ascoli Theorem, {v n } has a uniformly convergent subsequence in C[0,1]. Without loss of generality, let v n → v. Moreover, using the fact that
we can obtain that
This implies v ≡ 0 and this is a contradiction. Consequently, deg(I - Hμ-ε(·, τ), B(0, ε), 0) is well defined. Therefore, by the homotopy invariance theorem,
Similarly,
Let μ is k-th eigenvalue of (E p ). Then by Lemma 2.2, we get
This is a contradiction to the fact deg(Φ(∙, μ - ε), B(0,ε),0) = deg(Φ(∙, μ + ε), B(0, ε), 0).
Thus (0, μ) is a bifurcation point of (P).
Now, we shall adopt Rabinowitz's standard arguement [11]. Let denote the closure of the set of nontrivial solutions of (P) and denote the set such that u has exactly k - 1 simple zeros in (0,1), u > 0 near 0, and all zeros of u in [0,1] are simple. Let and . We note that the sets and are open in . Moreover, let denote the component of which meets (0, μ k ), where μ k = λ k (p). By the similar argument of Theorem 1.10 in [11], we can show the existence of two types of components emanating from (0, μ) contained in , when μ is an eigenvalue of (E p ); either it is unbounded or it contains , where is an eigenvalue of (E p ). The existence of a neighborhood of (0, μ k ) such that and imply is also proved in [11]. Actually, only the first alternative is possible as shall be shown next.
Lemma 3.5. Assume (Φ1), (Φ2), and (F1). Then, is unbounded in .
Proof: Suppose . Then since for j ≠ k, it follows from the above facts, must be unbounded in . Hence, Lemma 3.5 will be established once we show is impossible. It is clear that . Hence if , then there exists with and (u, λ) = limn → ∞(u n , λ n ), . If , u ≡ 0 because u dose not have double zero. Henceforth λ = μ j , j ≠ k. But then, for large n which is impossible by the fact that implies . The proof is complete.
Lemma 3.6. Assume (Φ1), (Φ2), (F 1), and (F3). Then for each k ∈ ℕ, there exists a constant M k ∈ (0, ∞) such that λ ≤ M k for every λ with .
Proof: Suppose it is not true, then there exists a sequence such that λ n → ∞. Let be the j th zero of u n . Then there exists j ∈ {1,..., k - 1} such that . Thus for each n, there exists such that . Let u n (t) > 0 for all . Suppose . Then by integrating the equation in (P) from to , we see that u n satisfies
For ,
Thus
The left side of (11) is bounded and independent on n, but the right side goes to ∞ as n → ∞. This is impossible. Now, if , then by integrating the equation in (P) from to , we see that u n satisfies
For
From the above argument, we get
This is impossible because the left side is bounded and independent on n, but the right side goes to infinity as n goes to infinity. We can get similar results when u n (t) < 0. Indeed, if , then we have
Also if , then we have
Since both (13) and (14) are impossible, there is no sequence satisfying λ n → ∞. Consequently, there exists an M k ∈ (0, ∞) such that λ ≤ M k .
Proof of Theorem 1.1
By Lemmas 3.3, 3.4, and 3.5, for any j ∈ ℕ, there exists an unbounded connected component of the set of nontrivial solutions emanating from (0, λ j (p)) such that implies u has exactly j - 1 simple zeros in (0,1). From Lemma 3.6, there is an M j such that implies that λ ≤ M j , and there are no nontrivial solutions of (P) for λ = 0, it follows that for any M > 0, there is such that ∥u∥1 > M. Hence, we can choose subsequence such that and ∥u n ∥1 → ∞. Thus, is a bifurcation point and .
4 Application and some examples
Proof of Theorem 1.2
Let us consider the bifurcation problem
Put f(t,u,λ) = -μϕ(u) + g(t, u). We can easily see that f(t,u,λ) = o(|ϕ(u)|) near zero uniformly for t and λ in bounded intervals. The equation in (A g ) can be equivalently changed into the following equation
By the similar argument in the proof of Theorem 1.1, for each k ≤ j ≤ n, there is a connected branch of solutions to (A f ) emanating from (0, λ j (p) - μ) which is unbounded in and such that implies that u has exactly j - 1 simple zeros in (0,1). From the fact ug(t, u) ≥ 0, it can be proved that there is an M j > 0 such that implies that λ ≤ M j , by the same argument as in the proof of Lemma 3.6. Since there is a constant K g > 0 such that g(t, s) ≤ K g ϕ(s) for all (t, s) ∈ [0,1] × ℝ, if , then λ > -K g . Hence will bifurcate from infinity also, which can only happen for λ = λ j (q) - ν. Since λ j (q) - ν < 0 < λ j (p) - μ and is connected, there exists u ≠ 0 such that . This u is a solution of (A). Since this is true for every such j, (A) has at least n - k + 1 nontrivial solutions.
Finally, we illustrate several examples of Theorems 1.1 and 1.2.
Example 4.1. Define ϕ, ψ, f by
Then ϕ and ψ are odd increasing homeomorphisms of ℝ and
Moreover, f satisfies f(t, u, λ) = o(|ψ(u)|) near zero and infinity, uniformly in t and λ, and uf(t,u, λ) ≥ 0. Therefore, all hypotheses of Theorem 1.1 are satisfied.
Example 4.2. Define ϕ, g by
Then ϕ is odd increasing homeomorphism of ℝ and
Moreover, ug(t,u) ≥ 0 and
Thus we can check on the fact that
All hypotheses of Theorem 1.2 for k = n = 1 are satisfied so that (A) possesses at least one nontrivial solution.
Example 4.3. Define ϕ, g by
Then ϕ is odd increasing homeomorphism of ℝ and
Moreover, ug(t,u) ≥ 0 and
Thus we can check on the fact that
All hypotheses of Theorem 1.2 for k = 1 and n = 3 are satisfied so that (A) possesses at least three nontrivial solutions.
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Acknowledgements
YH LEE was supported by the Mid-career Researcher Program through NRF grant funded by the MEST (No. 2010-0000377).
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Lee, E.K., Lee, YH. & Son, B. Global bifurcation results for general Laplacian problems. Fixed Point Theory Appl 2012, 7 (2012). https://doi.org/10.1186/1687-1812-2012-7
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DOI: https://doi.org/10.1186/1687-1812-2012-7