Open Access

Fixed point theorems on ordered gauge spaces with applications to nonlinear integral equations

Fixed Point Theory and Applications20122012:13

https://doi.org/10.1186/1687-1812-2012-13

Received: 29 November 2011

Accepted: 14 February 2012

Published: 14 February 2012

Abstract

We establish coincidence and fixed point theorems for mappings satisfying generalized weakly contractive conditions on the setting of ordered gauge spaces. Presented theorems extend and generalize many existing studies in the literature. We apply our obtained results to the study of existence and uniqueness of solutions to some classes of nonlinear integral equations.

Keywords

Gauge spaceordered setcoincidence pointfixed pointaltering distance function

1 Introduction

Fixed point theory is considered as one of the most important tools of nonlinear analysis that widely applied to optimization, computational algorithms, physics, variational inequalities, ordinary differential equations, integral equations, matrix equations and so on (see, for example, [16]). The Banach contraction principle [7] is a fundamental result in fixed point theory. It consists of the following theorem.

Theorem 1.1 (Banach[7]) Let (X, d) be a complete metric space and let T : XX be a contraction, i.e., there exists k [0, 1) such that d(Tx, Ty) ≤ kd(x, y) for all x, y X. Then T has a unique fixed point, that is, there exists a unique x* X such that Tx* = x*. Moreover, for any x X, the sequence {T n x} converges to x*.

Generalization of the above principle has been a heavily investigated branch of research (see, for example, [810]). In particular, there has been a number of studies involving altering distance functions. There are control functions which alter the distance between two points in a metric space. Such functions were introduced by Khan et al. [11], where they present some fixed point theorems with the help of such functions.

Definition 1.1 An altering distance function is a function ψ : [0, ∞) → [0, ∞) which satisfies

(a) ψ is continuous and nondecreasing;

(b) ψ(t) = 0 if and only if t = 0.

In [11], Khan et al. proved the following result.

Theorem 1.2 (Khan et al.[11]) Let (X, d) be a complete metric space, ψ be an altering distance function, c [0, 1) and T : XX satisfying
ψ ( d ( T x , T y ) ) c ψ ( d ( x , y ) ) ,

for all x, y X. Then T has an unique fixed point.

Altering distance has been used in metric fixed point theory in many studies (see, for example, [2, 3, 1219]). On the other hand, Alber and Guerre-Delabriere in [12] introduced a new class of contractive mappings on closed convex sets of Hilbert spaces, called weakly contractive maps.

Definition 1.2 (Alber and Guerre-Delabriere[12]) Let (E, · ) be a Banach space and C E a closed convex set. A map T : CC is called weakly contractive if there exists an altering distance function ψ : [0, ∞) → [0, ∞) with limt→∞ψ(t) = ∞ such that
T x - T y x - y - ψ ( x - y ) ,

for all x, y X.

In [12], Alber and Guerre-Delabriere proved the following result.

Theorem 1.3 (Alber and Guerre-Delabriere[12]) Let H be a Hilbert space and C H a closed convex set. If T : CC is a weakly contractive map, then it has a unique fixed point x* C.

Rhoades [18] proved that the previous result is also valid in complete metric spaces without the condition limt→∞ψ(t) = ∞.

Theorem 1.4 (Rhoades[18]) Let (X, d) be a complete metric space, ψ be an altering distance function and T : XX satisfying
d ( T x , T y ) d ( x , y ) - ψ ( d ( x , y ) )

for all x, y X. Then T has a unique fixed point.

Dutta and Choudhury [20] present a generalization of Theorems 1.2 and 1.4 proving the following result.

Theorem 1.5 (Dutta and Choudhury[20]) Let (X, d) be a complete metric space and T : XX be a mapping satisfying
ψ ( d ( T x , T y ) ) ψ ( d ( x , y ) ) - φ ( d ( x , y ) ) ,

for all x, y X, where ψ and φ are altering distance functions. Then T has an unique fixed point.

An extension of Theorem 1.5 was considered by Dorić [13].

Theorem 1.6 (Dorić[13]) Let (X, d) be a complete metric space and T : XX be a mapping satisfying
ψ ( d ( T x , T y ) ) ψ ( M ( x , y ) ) - φ ( M ( x , y ) ) ,
for all x, y X, where
M ( x , y ) = max d ( x , y ) , d ( T x , x ) , d ( T y , y ) , 1 2 [ d ( y , T x ) + d ( x , T y ) ] ,

ψ is an altering distance function and φ is a lower semi-continuous function with φ(t) = 0 if and only if t = 0. Then T has a unique fixed point.

Very recently, Eslamian and Abkar [14] (see also, Choudhury and Kundu [2]) introduced the concept of (ψ, α, β)-weak contraction and established the following result.

Theorem 1.7 (Eslamian and Abkar[14]) Let (X, d) be a complete metric space and T : XX be a mapping satisfying
ψ ( d ( T x , T y ) ) α ( d ( x , y ) ) - β ( d ( x , y ) ) ,
(1)
for all x, y X, where ψ, α, β : [0, ∞) → [0, ∞) are such that ψ is an altering distance function, α is continuous, β is lower semi-continuous,
α ( 0 ) = β ( 0 ) = 0 a n d ψ ( t ) - α ( t ) + β ( t ) > 0 f o r a l l t > 0 .

Then T has a unique fixed point.

Note that Theorem 1.7 seems to be new and original. Unfortunately, it is not the case. Indeed, the contractive condition (1) can be written as follows:
ψ ( d ( T x , T y ) ) ψ ( d ( x , y ) ) - φ ( d ( x , y ) ) ,
where φ : [0, ∞) → [0, ∞) is given by
φ ( t ) = ψ ( t ) - α ( t ) + β ( t ) , t 0 .

Clearly, from the hypotheses of Theorem 1.7, the function φ is lower semi-continuous with φ(t) = 0 if and only if t = 0. So Theorem 1.7 is similar to Theorem 1.6 of Dorić [13].

On the other hand, Ran and Reurings [6] proved the following Banach-Caccioppoli type principle in ordered metric spaces.

Theorem 1.8 (Ran and Reurings[6]) Let (X, ) be a partially ordered set such that every pair x, y X has a lower and an upper bound. Let d be a metric on X such that the metric space (X, d) is complete. Let f : XX be a continuous and monotone (i.e., either decreasing or increasing with respect to ) operator. Suppose that the following two assertions hold:

1. there exists k [0, 1) such that d(fx, fy) ≤ kd(x, y) for each x, y X with x y;

2. there exists x0 X such that x0 f x0or x0 f x0.

Then f has an unique fixed point x* X.

Nieto and Rodŕiguez-López [4] extended the result of Ran and Reurings for non-continuous mappings.

Theorem 1.9 (Nieto and Rodŕiguez-López[4]) Let (X, ) be a partially ordered set and suppose that there exists a metric d in X such that the metric space (X, d) is complete. Let T : XX be a nondecreasing mapping. Suppose that the following assertions hold:

1. there exists k [0, 1) such that d(Tx, Ty) ≤ kd(x, y) for all x, y X with x y;

2. there exists x0 X such that x0 Tx0;

3. if {x n } is a nondecreasing sequence in X such that x n x X as n → ∞, then x n x for all n.

Then T has a fixed point.

Since then, several authors considered the problem of existence (and uniqueness) of a fixed point for contraction type operators on partially ordered metric spaces (see, for example, [2, 3, 5, 1517, 19, 2138]).

In [3], Harjani and Sadarangani extended Theorem 1.5 of Dutta and Choudhury [20] to the setting of ordered metric spaces.

Theorem 1.10 (Harjani and Sadarangani[3]) Let (X, ) be a partially ordered set and suppose that there exists a metric d in X such that (X, d) is a complete metric space. Let T : XX be a nondecreasing mapping such that
ψ ( d ( T x , T y ) ) ψ ( d ( x , y ) ) - φ ( d ( x , y ) ) ,

for all x, y X with x y, where ψ and φ are altering distance functions. Also suppose either

(I) T is continuous or

(II) If {x n } X is a nondecreasing sequence with x n x X, then x n x for all n.

If there exists x0 X with x0 Tx0, then T has a fixed point.

In [16], Jachymski established a nice geometric lemma and proved that Theorem 1.10 of Harjani and Sadarangani can be deuced from an earlier result of O'Regan and Petruşel [33].

In this article, we present new coincidence and fixed point theorems in the setting of ordered gauge spaces for mappings satisfying generalized weak contractions involving two families of functions. Presented theorems extend and generalize many existing results in the literature, in particular Harjani and Sadarangani [3, Theorem 1.10], Nieto and Rodŕiguez-López [4, Theorem 1.9], Ran and Reurings [6, Theorem 1.8], and Dorić [13, Theorem 1.6]. As an application, existence results for some integral equations on the positive real axis are given.

Now, we shall recall some preliminaries on ordered gauge spaces and introduce some definitions.

2 Preliminaries

Definition 2.1 Let X be a nonempty set. A map d : X × X → [0, ∞) is called a pseudo-metric in X whenever
  1. (i)

    d(x, x) = 0 for all x X;

     
  2. (ii)

    d(x, y) = d(y, x) for all x, y X;

     
  3. (iii)

    d(x, y) ≤ d(x, z) + d(z, y) for all x, y, z X.

     
Definition 2.2 Let X be a nonempty set endowed with a pseudo-metric d. The d-ball of radius ε > 0 centered at x X is the set
B ( x ; d , ε ) = { y X | d ( x , y ) < ε } .

Definition 2.3 A family = { d λ | λ A } of pseudo-metrics is called separating if for each pair xy, there is a d λ such that d λ (x, y) ≠ 0.

Definition 2.4 Let X be a nonempty set and = { d λ | λ A } be a separating family of pseudo-metrics on X. The topology T ( ) having for a subbasis the family
( ) = { B ( x ; d λ , ε ) | x X , d λ , ε > 0 }

of balls is called the topology in X induced by the family . The pair ( X , T ( ) ) is called a gauge space. Note that ( X , T ( ) ) is Hausdorff because we require to be separating.

Definition 2.5 Let ( X , T ( ) ) be a gauge space with respect to the family = { d λ | λ A } of pseudo-metrics on X. Let {x n } be a sequence in X and x X.

(a) The sequence {x n } converges to x if and only if
λ A , ε > 0 , N N | d λ ( x n , x ) < ε , n N .

In this case, we denote x n x .

(b) The sequence {x n } is Cauchy if and only if
λ A , ε > 0 , N | d λ ( x n + p , x n ) < ε , n N , p .

(c) ( X , T ( ) ) is complete if and only if any Cauchy sequence in ( X , T ( ) ) is convergent to an element of X.

(d) A subset of X is said to be closed if it contains the limit of any convergent sequence of its elements.

Definition 2.6 Let = { d λ | λ A } be a family of pseudo-metrics on X. ( X , , ) is called an ordered gauge space if ( X , T ( ) ) is a gauge space and (X, ) is a partially ordered set.

For more details on gauge spaces, we refer the reader to [39].

Now, we introduce the concept of compatibility of a pair of self mappings on a gauge space.

Definition 2.7 Let ( X , T ( ) ) be a gauge space and f, g : XX are giving mappings. We say that the pair {f, g} is compatible if for all λ A , d λ (fgx n , gfx n ) → 0 as n → ∞ whenever {x n } is a sequence in X such that f x n t and g x n t for some t X.

Definition 2.8 (Ćirić et al.[29]) Let (X, ) be a partially ordered set and f, g : XX are two giving mappings. The mapping f is said to be g-nondecreasing if for all x, y X, we have
g x g y f x f y .

Definition 2.9 Let (X, ) be a partially ordered set. We say that (X, ) is directed if every pair of elements has an upper bound, that is, for every a, b X, there exists c X such that a c and b c.

3 Main results

Let ( X , T ( ) ) be a gauge space.

We consider the class of functions { ψ λ } λ A and { φ λ } λ A such that for all λ A , ψ λ , φ λ ,: [0, ∞) → [0, ∞) satisfy the following conditions:

(C1) ψ λ is an altering distance function.

(C2) φ λ is a lower semi-continuous function with φ λ (t) = 0 if and only if t = 0.

Our first result is the following.

Theorem 3.1 Let ( X , , ) be an ordered complete gauge space and let f, g : XX be two continuous mappings such that f is g-nondecreasing, f(X) g(X) and the pair {f, g} is compatible. Suppose that
ψ λ ( d λ ( f x , f y ) ) ψ λ ( d λ ( g x , g y ) ) - φ λ ( d λ ( g x , g y ) )
(2)

for all λ A , for all x, y X for which gx gy. If there exists x0such that gx0 fx0, then f and g have a coincidence point, that is, there exists a z X such that fz = gz.

Proof. Let x0 X such that gx0 fx0 (such a point exists by hypothesis). Since f(X) g(X), we can choose x1 X such that fx0 = gx1. Then gx0 fx0 = gx1. As f is g-nondecreasing, we get fx0 fx1. Continuing this process, we can construct a sequence {x n } in X such that
g x n + 1 = f x n , n = 0 , 1 ,
for which
g x 0 f x 0 = g x 1 f x 1 = g x 2 f x n - 1 = g x n
Then from (2), for all p, q , for all λ A , we have
ψ λ ( d λ ( f x p , f x q ) ) ψ λ ( d λ ( g x p , g x q ) ) - φ λ ( d λ ( g x p , g x q ) ) .
(3)

We complete the proof in the following three steps.

Step 1. We will prove that
d λ ( f x n , f x n + 1 ) 0 as n + , for all λ A .
(4)

Let λ A . We distinguish two cases.

  • First case: We suppose that there exists m such that d λ (fx m , fxm+1) = 0. Applying (3), we get that
    ψ λ ( d λ ( f x m + 1 , f x m + 2 ) ) ψ λ ( d λ ( g x m + 1 , g x m + 2 ) ) - φ λ ( d λ ( g x m + 1 , g x m + 2 ) ) = ψ λ ( d λ ( f x m , f x m + 1 ) ) - φ λ ( d λ ( f x m , f x m + 1 ) ) = ψ λ ( 0 ) - φ λ ( 0 ) ( from ( C 1 ) , ( C 2 ) ) = 0 .

Then it follows from (C1) that d λ (fxm+1, fxm+2) = 0. Continuing this process, one can show that d λ (fx n , fxn+1) = 0 for all nm. Then our claim (4) holds.

  • Second case: We suppose that
    d λ ( f x n , f x n + 1 ) > 0 , for all n .
    (5)
Let, if possible, for some n0 ,
d λ ( f x n 0 - 1 , f x n 0 ) < d λ ( f x n 0 , f x n 0 + 1 ) .
By the monotone property of ψ λ , and using (3), we get
ψ λ ( d λ ( f x n 0 - 1 , f x n 0 ) ) ψ λ ( d λ ( f x n 0 , f x n 0 + 1 ) ) ψ λ ( d λ ( g x n 0 , g x n 0 + 1 ) ) - φ λ ( d λ ( g x n 0 , g x n 0 + 1 ) ) = ψ λ ( d λ ( f x n 0 - 1 , f x n 0 ) ) - φ λ ( d λ ( f x n 0 - 1 , f x n 0 ) ) .
Then, by (C2), we have that d λ ( f x n 0 - 1 , f x n 0 ) = 0 , which contradicts (5). Therefore, we deduce that
d λ ( f x n , f x n + 1 ) d λ ( f x n - 1 , f x n ) , for all n 1 .
So, it follows that {d λ (fx n , fxn+1)} is a decreasing sequence of non-negative real numbers. Hence, there is r ≥ 0 such that
d λ ( f x n , f x n + 1 ) r as n + .
(6)
On the other hand, from (3), we have
ψ λ ( d λ ( f x n , f x n + 1 ) ) ψ λ ( d λ ( g x n , g x n + 1 ) ) - φ λ ( d λ ( g x n , g x n + 1 ) ) = ψ λ ( d λ ( f x n - 1 , f x n ) ) - φ λ ( d λ ( f x n - 1 , f x n ) ) .
This implies that
lim sup n ψ λ ( d λ ( f x n , f x n + 1 ) ) lim sup n ψ λ ( d λ ( f x n - 1 , f x n ) ) - lim inf n φ λ ( d λ ( f x n - 1 , f x n ) ) .
Then, using (6), the continuity hypothesis of ψ λ and the lower semi-continuity of φ λ , we get that
ψ λ ( r ) ψ λ ( r ) - φ λ ( r ) ,

which, by condition (C2) implies that r = 0. Thus, we proved (4).

Step 2. We will prove that {fx n } is a Cauchy sequence in the gauge space ( X , T ( ) ) . Suppose that {fx n } is not a Cauchy sequence. Then there exists ( λ , ε ) A × ( 0 , ) for which we can find two sequences of positive integers {m(k)} and {n(k)} such that for all positive integers k,
n ( k ) > m ( k ) > k , d λ ( f x m ( k ) , f x n ( k ) ) ε , d λ ( f x m ( k ) , f x n ( k ) - 1 ) < ε .
(7)
Using (7) and the triangular inequality, we get that
ε d λ ( f x n ( k ) , f x m ( k ) ) d λ ( f x m ( k ) , f x n ( k ) - 1 ) + d λ ( f x n ( k ) - 1 , f x n ( k ) ) < ε + d λ ( f x n ( k ) , f x n ( k ) - 1 ) .
Thus we have
ε d λ ( f x n ( k ) , f x m ( k ) ) < ε + d λ ( f x n ( k ) , f x n ( k ) - 1 ) .
Letting k → +∞ in the above inequality and using (4), we obtain
d λ ( f x n ( k ) , f x m ( k ) ) ε as k + .
(8)
On the other hand, we have
d λ ( f x n ( k ) , f x m ( k ) ) d λ ( f x n ( k ) , f x n ( k ) - 1 ) + d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) + d λ ( f x m ( k ) - 1 , f x m ( k ) )
and
d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) d λ ( f x n ( k ) - 1 , f x n ( k ) ) + d λ ( f x n ( k ) , f x m ( k ) ) + d λ ( f x m ( k ) , f x m ( k ) - 1 ) .
Thus we have
d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) d λ ( f x n ( k ) , f x m ( k ) ) - d λ ( f x n ( k ) , f x n ( k ) - 1 ) - d λ ( f x m ( k ) - 1 , f x m ( k ) ) d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) d λ ( f x n ( k ) - 1 , f x n ( k ) ) + d λ ( f x n ( k ) , f x m ( k ) ) + d λ ( f x m ( k ) - 1 )
which implies that
d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) - d λ ( f x n ( k ) , f x m ( k ) ) d λ ( f x n ( k ) - 1 , f x n ( k ) ) + d λ ( f x m ( k ) , f x m ( k ) - 1 ) .
Letting k → ∞ in the above inequality, using (4) and (8), we get that
d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) ε as k + .
(9)
Applying inequality (3) with p = n(k) and q = m(k), we get that
ψ λ ( d λ ( f x n ( k ) , f x m ( k ) ) ) ψ λ ( d λ ( g x n ( k ) , g x m ( k ) ) ) - φ λ ( d λ ( g x n ( k ) , g x m ( k ) ) ) ,
that is,
ψ λ ( d λ ( f x n ( k ) , f x m ( k ) ) ) ψ λ ( d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) ) - φ λ ( d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) ) .
Letting k → +∞ in the above inequality, using (8), (9), the continuity hypothesis of ψ λ and the lower semi-continuity of φ λ , we obtain
ψ λ ( ε ) ψ λ ( ε ) - φ λ ( ε ) ,

which implies from (C2) that ε = 0, which is a contradiction with ε > 0. Finally, we deduce that {fx n } is a Cauchy sequence.

Step 3. Existence of a coincidence point.

Since {fx n } is a Cauchy sequence in the complete gauge space ( X , T ( ) ) , then there exists a z X such that f x n z . Since f and g are continuous, we get that f f x n f z and g f x n g z . On the other hand, from gxn+1= fx n , we have also g x n z . Thus, we
f x n z , f f x n f z , g f x n g z , g x n z .
(10)
From the compatibility hypothesis of the pair {f, g}, we get that for all λ A ,
d λ ( f g x n , g f x n ) 0 as n .
(11)
Now, using the triangular inequality, for all λ A , we have
d λ ( f z , g z ) d λ ( f z , f f x n ) + d λ ( f g x n + 1 , g f x n + 1 ) + d λ ( g f x n + 1 , g z ) .

Letting n → ∞ in the above inequality, and using (10) and (11), we get that d λ (fz, gz) = 0 for all λ A . In the virtue of the separating structure of , this implies that fz = gz, that

is, z is a coincidence point of f and g.

Let ( X , , ) be an ordered gauge space. We consider the following assumption: (H): If {u n } X is a nondecreasing sequence with u n u X , then u n u for all n.

Theorem 3.2 Let ( X , , ) be an ordered complete gauge space satisfying the assumption (H). Let f, g : XX be two mappings such that f is g-nondecreasing, f(X) g(X) and g(X) is closed. Suppose that
ψ λ ( d λ ( f x , f y ) ) ψ λ ( d λ ( g x , g y ) ) - φ λ ( d λ ( g x , g y ) )
(12)

for all λ A , for all x, y X for which gx gy. If there exists x0such that gx0 fx0, then f and g have a coincidence point.

Proof. Following the proof of Theorem 3.1, we know that {gx n } is a Cauchy sequence in the ordered complete gauge space ( X , , ) . Since g(X) is closed, there exists z X such that g x n g z . Then we have
f x n g z and g x n g z .
(13)
Since {gx n } is a nondecreasing sequence, from (H), we have gx n gz for all n ≥ 1. Then we can apply (12) with x = x n and y = z, we obtain
ψ λ ( d λ ( f x n , f z ) ) ψ λ ( d λ ( g x n , g z ) ) - φ λ ( d λ ( g x n , g z ) )

for all λ A and n ≥ 1. Let λ A be fixed. Letting n → ∞ in the above inequality, using (C1), (C2) and (13), we obtain that ψ λ (d λ (gz, fz)) = 0, which implies from (C1) that d λ (gz, fz) = 0. Thus, we proved that d λ (gz, fz) = 0 for all λ A . Then gz = fz and z is a coincidence point of g and f.

Theorem 3.3 Let ( X , , ) be an ordered complete gauge space and f : XX be a nondecreasing mapping. Suppose that
ψ λ ( d λ ( f x , f y ) ) ψ λ ( d λ ( x , y ) ) - φ λ ( d λ ( x , y ) )
(14)
for all ( X , , ) , for all x, y X with x y. Also suppose either
  1. (I)

    f is continuous or

     
  2. (II)

    If {x n } X is a nondecreasing sequence with x n z X , then x n z for all n.

     

If there exists x0such that x0 fx0, then f has a fixed point, that is, there exists z X such that z = fz. Moreover, if(X, ) is directed, we obtain the uniqueness of the fixed point of f.

Proof. The existence of a fixed point of f follows immediately from Theorems 3.1 and 3.2 by taking g = I X (the identity mapping on X). Now, suppose that z' X is another fixed point of f, that is, z' = fz'. Since (X, ) is a directed set, there exists w X such that z w and z' w. Monotonicity of f implies that f n (z) f n (w) and f n (z') f n (w). Then we have
ψ λ ( d λ ( z , f n ( w ) ) ) ψ λ ( d λ ( f n - 1 ( z ) , f n - 1 ( w ) ) ) - φ λ ( d λ ( f n - 1 ( z ) , f n - 1 ( w ) ) ) ψ λ ( d λ ( f n - 1 ( z ) , f n - 1 ( w ) ) ) = ψ λ ( d λ ( z , f n - 1 ( w ) ) ) .
(15)
Since ψ λ is a nondecreasing function, we get that
d λ ( z , f n ( w ) ) d λ ( z , f n - 1 ( w ) ) , for all n 1 , λ A .
Then there exists r λ ≥ 0 such that d λ (z, f n (w)) → r λ as n → ∞. Letting n → ∞ in (15), we get that
ψ λ ( r λ ) ψ λ ( r λ ) - φ λ ( r λ ) ,

which implies that r λ = 0. Then we have f n ( w ) z . Similarly, one can show that f n ( w ) z . Since ( X , T ( ) ) is Hausdorff, we obtain that z = z'.

Let ( X , T ( ) ) be a gauge space and f, g : XX are two giving mappings. For all x, y X and λ A , we denote
M λ ( g x , g y ) = max d λ ( g x , g y ) , d λ ( g x , f x ) , d λ ( g y , f y ) , d λ ( g y , f y ) + d λ ( g y , f x ) 2 .

We shall prove the following result.

Theorem 3.4 Let ( X , , ) be an ordered complete gauge space and let f, g : XX be two continuous mappings such that f is g-nondecreasing, f(X) g(X) and the pair {f, g} is compatible. Suppose that
ψ λ ( d λ ( f x , f y ) ) ψ λ ( M λ ( g x , g y ) ) - φ λ ( M λ ( g x , g y ) )
(16)

for all λ A , for all x, y X for which gx gy. If there exists x0such that gx0 fx0, then f and g have a coincidence point.

Proof. Similarly to the proof of Theorem3.1, we can construct a sequence {x n } in X such that
g x n + 1 = f x n , n = 0 , 1 ,
for which
g x 0 g x 1 g x 2 g x n
Then from (16), for all p, q , for all λ A , we have
ψ λ ( d λ ( f x p , f x q ) ) ψ λ ( M λ ( g x p , g x q ) ) - φ λ ( M λ ( g x p , g x q ) ) .
(17)

We complete the proof in the following three steps.

Step 1. We will prove that
d λ ( f x n , f x n + 1 ) 0 as n + , for all λ A .
(18)

Let λ A . We distinguish two cases.

  • First case: We suppose that there exists m such that d λ (fx m , fxm+1) = 0. Applying (17), we get that
    ψ λ ( d λ ( f x m + 1 , f x m + 2 ) ) ψ λ ( M λ ( g x m + 1 , g x m + 2 ) ) - φ λ ( M λ ( g x m + 1 , g x m + 2 ) ) .
A simple computation gives us that
M λ ( g x m + 1 , g x m + 2 ) ) = d λ ( f x m + 1 , f x m + 2 ) .
Thus, we get that
ψ λ ( d λ ( f x m + 1 , f x m + 2 ) ) ψ λ ( d λ ( f x m + 1 , f x m + 2 ) ) - φ λ ( d λ ( f x m + 1 , f x m + 2 ) ) ,

which implies from (C2) that d λ (fxm+1, fxm+2) = 0. Continuing this process, one can show that d λ (fx n , fxn+1) = 0 for all nm. Then our claim (18) holds.

  • Second case: We suppose that
    d λ ( f x n , f x n + 1 ) > 0 , for all n N .
    (19)
Applying (17), for all n ≥ 1, we have
ψ λ ( d λ ( f x n , f x n + 1 ) ) ψ λ ( M λ ( g x n , g x n + 1 ) ) - φ λ ( M λ ( g x n , g x n + 1 ) ) .
(20)
A simple computation gives us that
M λ ( g x n , g x n + 1 ) = max { d λ ( f x n - 1 , f x n ) , d λ ( f x n , f x n + 1 ) } .
If M λ (gx n , gxn+1) = d λ (fx n , fxn+1), we get that
ψ λ ( d λ ( f x n , f x n + 1 ) ) ψ λ ( d λ ( f x n , f x n + 1 ) ) - φ λ ( d λ ( f x n , f x n + 1 ) ) ,
which implies from (C2) that d λ (fx n , fxn+1) = 0, that is a contradiction with (19). We deduce that M λ (gx n , gxn+1) = d λ (fxn-1, fx n ), that is, d λ (fx n , fxn+1) ≤ d λ (fxn-1, fx n ). So, it follows that {d λ (fxn-1, fx n )} is a decreasing sequence of non-negative real numbers. Hence, there is r ≥ 0 such that
d λ ( f x n - 1 , f x n ) r as n + .
(21)
On the other hand, from (20), we have
ψ λ ( d λ ( f x n , f x n + 1 ) ) ψ λ ( d λ ( f x n - 1 , f x n ) ) - φ λ ( d λ ( f x n - 1 , f x n ) ) .
Letting n → ∞ in the above inequality and using the properties (C1) and (C2), we get that
ψ λ ( r ) ψ λ ( r ) - φ λ ( r ) ,

which implies from (C2) that r = 0. Then our claim (18) holds.

Step 2. We will prove that {fx n } is a Cauchy sequence in the gauge space ( X , T ( ) ) . Suppose that {fx n } is not a Cauchy sequence. Then there exists ( λ , ε ) A × ( 0 , ) for which we can find two sequences of positive integers {m(k)} and {n(k)} such that for all positive integers k,
n ( k ) > m ( k ) > k , d λ ( f x m ( k ) , f x n ( k ) ) ε , d λ ( f x m ( k ) , f x n ( k ) - 1 ) < ε .
As in the proof of Theorem 3.1, one can show that
lim k d λ ( f x n ( k ) , f x m ( k ) ) = lim k d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) = ε .
(22)
Applying inequality (17) with p = n(k) and q = m(k), we get that
ψ λ ( d λ ( f x n ( k ) , f x m ( k ) ) ) ψ λ ( M λ ( g x n ( k ) , g x m ( k ) ) ) - φ λ ( M λ ( g x n ( k ) , g x m ( k ) ) ) .
(23)
On the other hand, we have
M λ ( g x n ( k ) , g x m ( k ) ) = max d λ ( g x n ( k ) , g x m ( k ) ) , d λ ( g x n ( k ) , f x n ( k ) ) , d λ ( g x m ( k ) , f x m ( k ) ) , d λ ( g x n ( k ) , f x m ( k ) ) + d λ ( g x m ( k ) , f x n ( k ) ) 2 = max d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) , d λ ( f x n ( k ) - 1 , f x n ( k ) ) , d λ ( f x m ( k ) - 1 , f x m ( k ) ) , d λ ( f x n ( k ) - 1 , f x m ( k ) ) + d λ ( f x m ( k ) - 1 , f x n ( k ) ) 2 .
Using the triangular inequality, we get that
d λ ( f x n ( k ) - 1 , f x m ( k ) ) - d λ ( f x n ( k ) , f x m ( k ) ) d ( f x n ( k ) - 1 , f x n ( k ) )
and
d λ ( f x m ( k ) - 1 , f x n ( k ) ) - d λ ( f x n ( k ) - 1 , f x m ( k ) - 1 ) d ( f x n ( k ) - 1 , f x n ( k ) ) .
Letting k → ∞ in the above inequalities and using (18), (22), we get that
lim k d λ ( f x n ( k ) - 1 , f x m ( k ) ) = lim k d λ ( f x m ( k ) - 1 , f x n ( k ) ) = ε .
(24)
Now, combining (18), (22), and (24), we obtain
M λ ( g x n ( k ) , g x m ( k ) ) ε as k .
(25)
Letting k → ∞ in (23), using (22), (25) and the properties of functions ψ λ and φ λ , we get that
ψ λ ( ε ) ψ λ ( ε ) - φ λ ( ε ) ,

which implies that ε = 0, a contradiction. Finally, we deduce that {fx n } is a Cauchy sequence.

Step 3. Existence of a coincidence point.

Since {fx n } is a Cauchy sequence in the complete gauge space ( X , T ( ) ) , then there exists a z X such that f x n z . The rest part of the proof is similar to that of Theorem 3.1.

Theorem 3.5 Let ( X , , ) be an ordered complete gauge space satisfying the assumption (H). Let f, g : XX be two mappings such that f is g-nondecreasing, f(X) g(X) and g(X) is closed. Suppose that
ψ λ ( d λ ( f z , f y ) ) ψ λ ( M λ ( g x , g y ) ) - φ λ ( M λ ( g x , g y ) )

for all λ A , for all x, y X for which gx gy. If there exists x0such that gx0 fx0, then f and g have a coincidence point.

Proof. It is similar to the proof of Theorem 3.2.

Using the same technique of the proof of Theorem 3.3, we deduce from Theorems 3.4 and 3.5 the following fixed point result.

Theorem 3.6 Let ( X , , ) be an ordered complete gauge space and f : XX be a nondecreasing mapping. Suppose that
ψ λ ( d λ ( f x , f y ) ) ( ψ λ - φ λ ) max d λ ( x , y ) , d λ ( x , f x ) , d λ ( y , f y ) , d λ ( x , f y ) + d λ ( y , f x ) 2
for all λ A , for all x, y X with x y. Also suppose either
  1. (I)

    f is continuous or

     
  2. (II)

    If {x n } X is a nondecreasing sequence with x n z X , then x n z for all n.

     

If there exists x0such that x0 f x0, then f has a fixed point. Moreover, if (X, ) is directed, we obtain the uniqueness of the fixed point of f.

4 Some consequences

In this section, we present some fixed point theorems of integral-type on ordered gauge spaces, deduced from our previous obtained results.

Let Γ be the set of functions a : [0, ∞) → [0, ∞) satisfying
  1. (i)

    a is locally integrable on [0, ∞).

     
  2. (ii)

    For all ε > 0, we have 0 ε a ( t ) d t > 0 .

     
Theorem 4.1 Let ( X , , ) be an ordered complete gauge space and let f, g : XX be two continuous mappings such that f is g-nondecreasing, f(X) g(X) and the pair {f, g} is compatible. Suppose that
0 d λ ( f x , f y ) a λ ( t ) d t 0 d λ ( g x , g y ) a λ ( t ) d t - 0 d λ ( g x , g y ) b λ ( t ) d t

for all λ A , for all x, y X for which gx gy, where a λ , b λ Γ for all λ A . If there exists x0such that gx0 fx0, then f and g have a coincidence point.

Proof. It follows from Theorem 3.1, by taking for all λ A ,
ψ λ ( t ) = 0 t a λ ( s ) d s and φ λ ( t ) = 0 t b λ ( s ) d s , t 0 .

It is clear that for all λ A , the functions ψ λ and ϕ λ satisfy conditions (C1) and (C2).

Theorem 4.2 Let ( X , , ) be an ordered complete gauge space satisfying the assumption (H). Let f, g : XX be two mappings such that f is g-nondecreasing, f(X) g(X) and g(X) is closed. Suppose that
0 d λ ( f x , f y ) a λ ( t ) d t 0 d λ ( g x , g y ) a λ ( t ) d t - 0 d λ ( g x , g y ) b λ ( t ) d t

for all λ A , for all x, y X for which gx gy, where a λ , b λ Γ for all λ A . If there exists x0such that gx0 fx0, then f and g have a coincidence point.

Proof. It follows from Theorem 3.2.

Theorem 4.3 Let ( X , , ) be an ordered complete gauge space and f : XX be a nondecreasing mapping. Suppose that
0 d λ ( f x , f y ) a λ ( t ) d t 0 d λ ( x , y ) a λ ( t ) d t - 0 d λ ( x , y ) b λ ( t ) d t
for all λ A , for all x, y X with x y, where a λ , b λ Γ for all λ A . Also suppose either
  1. (I)

    f is continuous or

     
  2. (II)

    If {x n } X is a nondecreasing sequence with x n z X , then x n z for all n.

     

If there exists x0such that x0 fx0, then f has a fixed point. Moreover, if (X, ) is directed, we obtain the uniqueness of the fixed point of f.

Proof. It follows from Theorem 3.3.

Theorem 4.4 Let ( X , , ) be an ordered complete gauge space and let f, g : XX be two continuous mappings such that f is g-nondecreasing, f(X) g(X) and the pair {f, g} is compatible. Suppose that
0 d λ ( f x , f y ) a λ ( t ) d t 0 M λ ( g x , g y ) a λ ( t ) d t - 0 M λ ( g x , g y ) b λ ( t ) d t

for all λ A , for all x, y X for which gx gy, where a λ , b λ Γ for all λ A . If there exists x0such that gx0 fx0, then f and g have a coincidence point.

Proof. It follows from Theorem 3.4.

Theorem 4.5 Let ( X , , ) be an ordered complete gauge space satisfying the assumption (H). Let f, g : XX be two mappings such that f is g-nondecreasing, f(X) g(X) and g(X) is closed. Suppose that
0 d λ ( f x , f y ) a λ ( t ) d t 0 M λ ( g x , g y ) a λ ( t ) d t - 0 M λ ( g x , g y ) b λ ( t ) d t

for all λ A , for all x, y X for which gx gy, where a λ , b λ Γ for all λ A . If there exists x0such that gx0 fx0, then f and g have a coincidence point.

Proof. It follows from Theorem 3.5.

Theorem 4.6 Let ( X , , ) be an ordered complete gauge space and f : XX be a nondecreasing mapping. Suppose that
0 d λ ( f x , f y ) a λ ( t ) d t 0 M λ ( x , y ) a λ ( t ) d t - 0 M λ ( x , y ) b λ ( t ) d t
for all λ A , for all x, y X with x y, where a λ , b λ Γ for all λ A . Also suppose either
  1. (I)

    f is continuous or

     
  2. (II)

    If {x n } X is a nondecreasing sequence with x n z X , then x n z for all n.

     

If there exists x0such that x0 fx0, then f has a fixed point. Moreover, if (X, ) is directed, we obtain the uniqueness of the fixed point of f.

Proof. It follows from Theorem 3.6.

5 Applications

In this section, we present some examples of nonlinear integral equations, where our obtained results can be applied.

Consider the integral equation
x ( t ) = 0 t k ( t , s , x ( s ) ) d s + h ( t ) , t 0 ,
(26)

where k : [0, ∞) × [0, ∞) × and h : [0, ∞) → .

Previously, we consider the space X = C([0, ∞), ) of real continuous functions defined on [0, ∞). For each positive integer n ≥ 1, we define the map · n : X → [0, ∞) by
x n = max 0 t n x ( t ) , for all x X .
This map is a semi-norm on X. Define now,
d n ( x , y ) = x - y n , for all n 1 , x , y X .
Then = { d n } n 1 is a separating family of pseudo-metrics on X. The gauge space ( X , T ( ) ) with respect to the family is complete. Consider on X the partial order defined by
x , y X , x y x ( t ) y ( t ) for all t 0 .

For any increasing sequence {x n } in X converging to some z X we have x n (t) ≤ z(t) for any t ≥ 0. Also, for every x, y X, there exists c(x, y) X which is comparable to x and y.

We shall prove the following result.

Theorem 5.1 Suppose that

(i) k : [0, ∞) × [0, ∞) × and h : [0, ∞) → are continuous;

(ii) k(t, s, ·): is increasing for each t, s ≥ 0;

(iii) for each t, s ≥ 0, u, v , uv, we have
k ( t , s , u ) - k ( t , s , v ) γ ( t , s ) ln [ ( v - u ) 2 + 1 ] ,
where γ : [0, ∞) × [0, ∞) → [0, ∞) is continuous, the function t 0 t γ ( t , s ) d s is bounded on [0, ∞) and
sup t 0 0 t γ ( t , s ) d s 1 ;
(iv) there exists x0 C([0, ∞), ) such that
x 0 ( t ) 0 t k ( t , s , x 0 ( s ) ) d s + h ( t ) , f o r a n y t 0 .

Then the integral equation (26) has a unique solution x* C([0, ∞), ).

Proof. Consider the operator f : XX given by
f x ( t ) = 0 t k ( t , s , x ( s ) ) d s + h ( t ) , t 0 , x X .

It is clear that f is well defined since k and h are continuous functions.

From condition (ii), for every x, y X with x y, we have
k ( t , s , x ( s ) ) k ( t , s , y ( s ) ) , for all t , s 0 ,
which implies that
0 t k ( t , s , x ( s ) ) d s + h ( t ) 0 t k ( t , s , y ( s ) ) d s + h ( t ) , for all t 0 ,

that is, fx fy. This proves that f is a nondecreasing operator.

Taking into account (iii), for each x, y X with x y, for all t [0, n], n ≥ 1, we have
f x ( t ) - f y ( t ) 0 t k ( t , s , y ( s ) ) - k ( t , s , x ( s ) ) d s 0 t γ ( t , s ) ln [ ( y ( s ) - x ( s ) ) 2 + 1 ] d s ln [ ( d n ( x , y ) ) 2 + 1 ] 0 t γ ( t , s ) d s ln [ ( d n ( x , y ) ) 2 + 1 ] .
Then, for all n ≥ 1, we have
d n ( f x , f y ) ln [ ( d n ( x , y ) ) 2 + 1 ] , for all x , y X , x y .
Hence, for all n ≥ 1, we have
ψ n ( d n ( f x , f y ) ) ψ n ( d n ( f x , f y ) ) - φ n ( d n ( f x , f y ) ) , for all x , y X , x y ,

where ψ n (t) = t2 and φ n (t) = t2 - ln(t2 + 1). Obviously, ψ n , φ n satisfy the conditions (C1) and (C2). Moreover, from (iv), there exists x0 X such that x0 f x0.

Now, applying Theorem 3.3, we obtain that f has a unique fixed point x* X, that is, x* C([0, ∞), ) is the unique solution to (26).

Consider now the integral equation
x ( t ) = - t 2 t 2 k ( t , s , x ( s ) ) d s + h ( t ) , t ,
(27)

where k : × × and h : .

We consider the space X = C(, ) of real continuous functions defined on . For each positive integer n ≥ 1, we define the map · n : X → [0, ∞) by
x n = max - n t n x ( t ) , for all x X .
This map is a semi-norm on X. Define now,
d n ( x , y ) = x - y n , for all n 1 , x , y X .
Then = { d n } n 1 is a separating family of pseudo-metrics on X. The gauge space ( X , T ( ) ) with respect to the family is complete. As before, consider on X the partial order defined by
x , y X , x y x ( t ) y ( t ) for all t .

For any increasing sequence {x n } in X converging to some z X we have x n (t) ≤ z(t) for any t . Also, for every x, y X, there exists c(x, y) X which is comparable to x and y. We shall prove the following result.

Theorem 5.2 Suppose that

(i) k : × × and h : are continuous;

(ii) k(t, s, ·): is increasing for each t, s ;

(iii) for each t, s , u, v , uv, we have
k ( t , s , u ) - k ( t , s , v ) γ ( t , s ) ln [ ( v - u ) 2 + 1 ] ,
where γ : × → [0, ∞) is continuous, the function t - t 2 t 2 γ ( t , s ) d s is bounded on and
sup t - t 2 t 2 γ ( t , s ) d s 1 ;
(iv) there exists x0 C(, ) such that
x 0 ( t ) 0 t k ( t , s , x 0 ( s ) ) d s + h ( t ) , for any t .

Then the integral equation (27) has a unique solution x* C(, ).

Proof. Consider the operator f : XX given by
f x ( t ) = - t 2 t 2 k ( t , s , x ( s ) ) d s + h ( t ) , t R , x X .
From condition (ii), for every x, y X with x y, we have
k ( t , s , x ( s ) ) k ( t , s , y ( s ) ) , for all t , s R ,
which implies that
- t 2 t 2 k ( t , s , x ( s ) ) d s + h ( t ) - t 2 t 2 k ( t , s , y ( s ) ) d s + h ( t ) , for all t R ,

that is, fx fy. This proves that f is a nondecreasing operator.

Taking into account (iii), for each x, y X with x y, for all t [-n, n], n ≥ 1, we have
f x ( t ) - f y ( t ) - t 2 t 2 k ( t , s , y ( s ) ) - k ( t , s , x ( s ) ) d s - t 2 t 2 γ ( t , s ) ln [ ( y ( s ) - x ( s ) ) 2 + 1 ] d s ln [ ( d n ( x , y ) ) 2 + 1 ] - t 2 t 2 γ ( t , s ) d s ln [ ( d n ( x , y ) ) 2 + 1 ] .
Then, for all n ≥ 1, we have
d n ( f x , f y ) ln [ ( d n ( x , y ) ) 2 + 1 ] , for all x , y X , x y .
Hence, for all n ≥ 1, we have
ψ n ( d n ( f x , f y ) ) ψ n ( d n ( f x , f y ) ) - φ n ( d n ( f x , f y ) ) , for all x , y X , x y ,

where ψ n (t) = t2 and φ n (t) = t2 - ln(t2 + 1). Moreover, from (iv), there exists x0 X such that x0 fx0.

Now, applying Theorem 3.3, we obtain that f has a unique fixed point x* X that is, x* C(, ) is the unique solution to (27).

Declarations

Authors’ Affiliations

(1)
FST Campus Universitaire
(2)
Ecole Supérieure des Sciences et Techniques de Tunis

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© Cherichi and Samet; licensee Springer. 2012

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