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TableĀ 3 Table of values choosing \(x_{0}=1\), \(x_{1}=2.5\)

From: A hybrid inertial algorithm for approximating solution of convex feasibility problems with applications

n Algorithm (3.12)
\(|x_{n+1}|\)
1 2.5
2 1
3 0.0598
4 0.0598
5 0.0465
10 0.0044
20 \(1.425\times e^{-5}\)
30 \(5.549\times e^{-8}\)
40 \(8.18\times e^{-11}\)
50 \(2.408\times e^{-13}\)
55 \(3.521\times e^{-15}\)