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Table 2 The values of { z n } , { y n } , and { x n } with initial value x 1 =−10

From: An iterative algorithm for system of generalized equilibrium problems and fixed point problem

 

Algorithm 3.1

Algorithm 3.2 with F= F 1

Algorithm 3.2 with F= F 2

z n

y n

x n

z n

y n

x n

z n

y n

x n

n = 1

−0.714286

−0.238095

−10.000000

−2.857143

−0.952381

−10.000000

−2.500000

−0.833333

−10.000000

n = 2

−0.177527

−0.162733

−3.538711

−0.924273

−0.847250

−4.005183

−0.853791

−0.782642

−3.927438

n = 3

−0.081028

−0.079027

−1.869430

−0.513819

−0.501132

−2.440639

−0.487908

−0.475861

−2.369839

n = 4

−0.043427

−0.042974

−1.085664

−0.317798

−0.314488

−1.588992

−0.307701

−0.304496

−1.538505

n = 5

−0.025092

−0.024958

−0.659998

−0.206325

−0.205225

−1.066013

−0.202795

−0.201714

−1.032413

n = 6

−0.015158

−0.015111

−0.412926

−0.137783

−0.137358

−0.728280

−0.137124

−0.136701

−0.706715

n = 7

−0.009444

−0.009426

−0.263964

−0.093772

−0.093590

−0.504027

−0.094344

−0.094161

−0.490588

n = 8

−0.006031

−0.006023

−0.171898

−0.064738

−0.064654

−0.352462

−0.065776

−0.065690

−0.344356

n = 9

−0.003937

−0.003934

−0.113970

−0.045226

−0.045185

−0.248745

−0.046372

−0.046330

−0.244064

n = 10

−0.002627

−0.002626

−0.077009

−0.031937

−0.031916

−0.177107

−0.033029

−0.033007

−0.174582