Skip to main content

Table 10 Absolute error of Example 2.2 for different values of λ and γ ( x=0.4 and x=0.6 respectively)

From: The new modified Ishikawa iteration method for the approximate solution of different types of differential equations

 

x = 0.2

x = 0.4

x = 0.6

λ = 0.5, γ = 0.5

0.0010268706

0.00942023

0.036214166

λ = 0.5, γ = 0.25

0.001726984648

0.015021141

0.055117245

λ = 0.25, γ = 0.5

0.001282485736

0.011465151

0.043115775

λ = 0.25, γ = 0.25

0.00198457568

0.017081869

0.017774779

λ = 0.75, γ = 0.25

0.001217348504

0.010944053

0.041357069

λ = 0.25, γ = 0.75

0.000672182488

0.006582725

0.026637587

λ = 0.75, γ = 0.75

0.000343930328

0.003956708

0.017774779

Picard

0.00000000522

0.000000684

0.000012

Runge-Kutta

0.000998849654

0.001220066

0.001491752

Euler

0.00280551632

0.015649395

0.0426376